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3 years ago

7

Please i will give brainlist

1 answer:

ElenaW [278]3 years ago

5 0

Answer:

the second answer

y=1/2x+3/4

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In the function f(x) = 4(x2 − 6x + ____) + 20, what number belongs in the blank to complete the square?

Savatey [412]

The right answer for the question that is being asked and shown above is that: In the function f(x) = 4(x2 − 6x + ____) + 20, what number belongs in the blank to complete the square?

x2 - 6x + 9

So the answer on the blank space is 9. It should be a perfect square.
= 6/2
= 3^2
= 9
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3 0

3 years ago

Philly and Boston were working on a project in carpentry class. They needed to cut 5 lengths of 2 3/4 feet from a board. How lon

Anna71 [15]

The board must be at least as big as the project's length needed,
so, it needs to be at least $\left( 2\frac{3}{4} \right)+\left( 2\frac{3}{4} \right)+\left( 2\frac{3}{4} \right)+\left( 2\frac{3}{4} \right)+\left( 2\frac{3}{4} \right)
\\ \quad \\
or
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5\cdot \left( 2\frac{3}{4} \right)\implies \boxed{?}$

3 0

3 years ago

Read 2 more answers

What is an equation of the line that passes through the point (-4,-6) and is perpendicular to the line 4x+5y=25

elixir [45]

Answer:

$y = \frac{5}{4} x - 1$

Step-by-step explanation:

The equation of a line is usually written in the form of y=mx+c, where m is its gradient and c is its y-intercept.

First rewrite the equation of the given line in the form of y=mx +c.

4x+5y=25

5y= -4x +25

$y = - \frac{4}{5} x + 5$

The gradient of the given line is $- \frac{4}{5}$

The product of the gradient of perpendicular lines is -1.

$( - \frac{4}{5} )(gradient \: of \: line) = - 1 \\ gradient \: of \: line = - 1 \div ( - \frac{4}{5} ) \\ gradient \: of \: line = \frac{5}{4}$

Thus, m= $\frac{5}{4}$

$y = \frac{5}{4} x + c$

Substitute a coordinate to find c.

When x= -4, y= -6,

$- 6 = \frac{5}{4} ( - 4) + c \\ - 6 = - 5 + c \\ c = 5 - 6 \\ c = - 1$

Hence, the equation of the line is

$y = \frac{5}{4} x - 1$

7 0

3 years ago

What number raise to the -2 exponet would equal 1/4

Svetradugi [14.3K]

So x^2 = 1/4. Take square root of each side

6 0

4 years ago

If XD = 2X – 6 and XV = 3x – 6 and WY and XV bisect at D, what is XV?

frez [133]

The diagonal WY bisects the diagonal XV at point D, which means that XV is divided into two equal line segments XD and XV.

$XD=XV$

Replace the equation above with the given expressions for both line segments:

XD= 2x-6

XV= 3x-6

$2x-6=3x-6$

$undefined$

5 0

1 year ago