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Lana71 [14]
3 years ago
6

CAN SOMEONE HELP ME WITH THIS, PLEASE AND THANK YOU.

Mathematics
2 answers:
Maru [420]3 years ago
8 0

Answer: 9 6/20

Hope that helps :)

Orlov [11]3 years ago
7 0

Answer:9 6/20

Step-by-step explanation:

add numerator and find lcf on denominator add whole number

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Choose True or False for each statement.
madreJ [45]

Answer:

1) True

2) True

3) False

4) True

Step-by-step explanation:

1) You can compare irrational numbers using rational approximations

The above statement is true as given two irrational numbers which can be expressed in decimal format, by rounding up the numbers to a certain number of decimal places, the values of the irrational numbers will be different

2) Square roots can be compared and ordered by comparing and ordering the numbers underneath the radical symbol

The above statement is true as the the values of the numbers under the radical symbol are directly proportional to the square root

3) You cannot compare the value of rational and irrational numbers

The above statement is false because the value of an irrational number can be found between two rational numbers. Therefore, the value of an irrational number is higher than the rational number that precedes it on the left of a number line

4) The closer the numbers being compared, the more decimal places you need to use

The above statement is true as a higher level of detailed value of the numbers being compared will be required given the closeness in value of the numbers being compared.

7 0
3 years ago
Plz Help!!!!!!!!!!!!!!!!!!!!!!!!!
Novosadov [1.4K]

Answer:

line segments j' k' and m' n' do not intersect and are the same distance apart as jk and mn

Step-by-step explanation:

this is because if jk and mn are both moved to the left two units, the space between them does not change

4 0
3 years ago
If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?
lys-0071 [83]

Answer:

2

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

3x^2-(3k-2)x-(k-6) \text{ with }k=2:

3x^2-(3\cdot 2-2)x-(2-6)

3x^2-4x+4

I'm going to solve 3x^2-4x+4=0 for x using the quadratic formula:

\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}

\frac{4\pm \sqrt{16-16(3)}}{6}

\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}

\frac{4\pm 4\sqrt{-2}}{6}

\frac{2\pm 2\sqrt{-2}}{3}

\frac{2\pm 2i\sqrt{2}}{3}

Let's see if uv=u+v holds.

uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}

Keep in mind you are multiplying conjugates:

uv=\frac{1}{9}(4-4i^2(2))

uv=\frac{1}{9}(4+4(2))

uv=\frac{12}{9}=\frac{4}{3}

Let's see what u+v is now:

u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}

u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}

We have confirmed uv=u+v for k=2.

4 0
2 years ago
The given value below figure find the value of x
tino4ka555 [31]

Answer:

<h2>x = 117°</h2>

Step-by-step explanation:

We know:

The sum of the quadrilateral angles measures 360°.

Therefore we have the equation:

30^o+39^o+48^o+m\angle D=360^o\qquad(1)

The sum of angles x and D is equal to 360°. Therefore we have the other equation:

x+m\angle D=360^o\qquad(2)

From (1) and (2) we have:

x+m\angle D=30^o+39^o+48^o+m\angle D\qquad\text{subtract}\ m\angle D\ \text{from both sides}\\\\x=30^o+39^o+48^o\\\\x=117^o

6 0
3 years ago
In the figures, ΔCDA ≈ ΔXYZ
Svetradugi [14.3K]
CD = XY = 26 mm
hope that helps
3 0
3 years ago
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