Answer:
C, 3y(2y+9)
Step-by-step explanation:
you can factor out a 3 from both 6 and 27, as well as a y from both so you would put them on the outside as shown in C. Hope that helped! Let me know if you need more of an explanation, and id be happy to help!
6y^2+27y
6 and 27 both have a common factor, meaning that the same number can go in to them both, 3. Because both 6 and 27 have a y, you are able to also take out a y so outside would be 3y.
so the answer is 3y(2y+9)
