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KatRina [158]
3 years ago
12

Please help me thank you

Mathematics
1 answer:
gayaneshka [121]3 years ago
5 0

Answer:

x = 6

Step-by-step explanation:

First, separate the problem into -\frac{2x}{3} +9=\frac{4x}{3} - 3

Then, Subtract 9 from both sides of the equation. -\frac{2x}{3} +9-9=\frac{4}{3} * x - 3-9

Simplify. -\frac{2x}{3}=\frac{4x}{3}-12

Multiply 3 to each side, which will give you -2x = 4x - 36

Subtract 4x from each side  -2x - 4x = 4x - 36x - 4x

Combine like terms: -6x = -36

Divide both sides by -6

Your answer should be 6

<em>(sorry for the late answer)</em>

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Help me solve this problem step by step because I’m having a hard time
jarptica [38.1K]

Answer:

x=3, y=10

Step-by-step explanation:

in triangle KLN all the angles are equal making it an equilateral trianlge. GIven one side being 6, we know all the sides are 6 including the side with the expression y-4.

this means

y-4=6

y=10

Using the converse of the base angles theorem(meaning we know the base angles are congruent so the two sides are conguent), we know that

6=x+3

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4 0
2 years ago
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sergij07 [2.7K]

Answer:

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Step-by-step explanation:

8 0
2 years ago
To decrease the impact on the environment, factory chimneys must be high enough to allow pollutants to dissipate over a larger a
Komok [63]

Answer:

The probability hat the sample mean height for the 40 chimneys is greater than 102 meters is 0.1469.

Step-by-step explanation:

Let the random variable <em>X</em> be defined as the height of chimneys in factories.

The mean height is, <em>μ</em> = 100 meters.

The standard deviation of heights is, <em>σ</em> = 12 meters.

It is provided that a random sample of <em>n</em> = 40 chimney heights is obtained.

According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

Since the sample selected is quite large, i.e. <em>n</em> = 40 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean heights of chimneys.

\bar X\sim N(\mu_{\bar x},\ \sigma^{2}_{\bar x})

Compute the probability hat the sample mean height for the 40 chimneys is greater than 102 meters as follows:

P(\bar X>102)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}})>\frac{102-100}{12/\sqrt{40}})

                    =P(Z>1.05)\\=1-P(Z

*Use a <em>z</em>-table fr the probability.

Thus, the probability hat the sample mean height for the 40 chimneys is greater than 102 meters is 0.1469.

8 0
3 years ago
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What is the domain of the function y=xVx?<br> - 0 0 0 O 15x&lt;0
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Answer:

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Step-by-step explanation:

hope it helps...

have a great day!!

4 0
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