Using the line of the best fit, the predicted student's score in English test is 48
<h3>How to determine the student's score in English?</h3>
From the question, we have:
Mathematics score = 60
The scores in English tests are plotted on the y-axis.
On the given graph, we have:
(x,y) = (60,48)
This means that when x = 60, the value of y is 48
This in other words means that the student's score in English test is 48
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So, 40 Customers are waiting at 10 A.M.
According to statement
Number of customers arrives at coffee shop per hour = 100
Capacity of shop for per minute per customer = 0.8 minute
Capacity of shop for customers per hour = 80
Find number of customers are by
Queue growth rate = Demand - Capacity
Put the values in the formula and find the growth rate
So,
Queue growth rate= 100 - 80 = 20.
Length of queue at 10 a.m. = 2 × 20 = 40.
So, 40 Customers are waiting at 10 A.M.
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Answer:
Solution : 8i
Step-by-step explanation:
We can use the trivial identities cos(π / 2) = 0, and sin(π / 2) = 1 to solve this problem. Let's substitute,
![8\left[cos\left(\frac{\pi }{2}\right)+isin\left(\frac{\pi \:}{2}\right)\right]](https://tex.z-dn.net/?f=8%5Cleft%5Bcos%5Cleft%28%5Cfrac%7B%5Cpi%20%7D%7B2%7D%5Cright%29%2Bisin%5Cleft%28%5Cfrac%7B%5Cpi%20%5C%3A%7D%7B2%7D%5Cright%29%5Cright%5D)
= 
And of course 1i = i, so we have the expression 8(0 + i ). Distributing the " 8, " 8( 0 ) = 0, and 8(i) = 8i, making the fourth answer the correct solution.
We can solve this by finding one of the numbers first
Let the smaller number be y.
Since these 2 numbers are consecutive odd numbers, the larger number should be 2 more than the smaller one (y+2).
Therefore,
y + (y+2) = 284
2y +2 = 284
shift +2 to the other side and turn it into -2
2y = 284 - 2
2y = 282
shift x2 to the other side and turn it into /2
y = 282/2
y = 141
Now we got the smaller number, which is 141, we can also find the larger number by adding 2 to it. 141+2 = 143,
Therefore, your answer is 141 and 143
You did not include the problem therefore i cannot help you with this but if you could message me the problem i’d be happy too
