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hichkok12 [17]
3 years ago
6

Are triangles ABC and EBC congruent?

Mathematics
2 answers:
Alekssandra [29.7K]3 years ago
8 0

Answer:

I think it is: Yes, by SAS but not sure...

Step-by-step explanation:

fredd [130]3 years ago
3 0

Answer:

yes

Step-by-step explanation:

connect dc to <abc and you have a triangle

connect bc to <ebc and you have the same triangle just reflected over the y axis

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List S and list T each contain 5 positive integers, and for each list the average (arithmetic mean) of the integers in the list
gtnhenbr [62]

Answer:

Yes, SDS > SDT

Step-by-step explanation:

List S

25, 30, 40, 50, XS

Average list S = 40

So, we could write,

Average list S = 40 = (25 + 30 + 40 + 50 + XS) / 5

Solving for XS

XS = 40 x 5 – 25 – 30 – 40 – 50 = 200 – 145 = 55  

SDs = SD (25, 30, 40, 50, 55) = 12.74

List T

30, 40, 45, 50, XT

Average list T = 40

So, we could write,

Average list T = 40 = (30 + 40 + 45 + 50 + XT) / 5

Solving for XT

XT = 40 x 5 – 30 – 40 – 45 – 50 = 200 – 165 = 35  

SDT = SD (30, 35, 40, 45, 50) = 7.1

Even at first sight SDS > SDT  because 25 is out of the range 30-50, while 45 is within that range.

List S is more spread than list T.

3 0
3 years ago
Is everyone answering so we can ask more questions lol
kolbaska11 [484]

Answer: yes  

Step-by-step explanation:

Lol

8 0
2 years ago
Pls answer for brainlest and 50 points PLEASE EXPLAIN <br><br> In image
Mumz [18]
Answer: C) 163

Step-by-Step Solution:

In the Right Triangle formed to the extreme right, lets mark the angles as
∠1, ∠2 and ∠3.

Therefore, from the Figure :-

∠1 = 73°
∠2 = 90°

By Angle Sum Property :-

∠3 = 180 - (73 + 90)
∠3 = 180 - 163
=> ∠3 = 17°

The Angle which forms a Linear Pair with ∠3 is the Corresponding Angle of ∠r, and Corresponding Angles are Equal.

Therefore,
=> 180 - ∠3
= 180 - 17
=> 163°

Therefore, the Angle that forms the Linear Pair with ∠3 is 163°

This Angle is Corresponding to ∠r and hence they are Equal ie. ∠r = 163°

Hence, ∠r = 163°
8 0
1 year ago
Read 2 more answers
Hiram raises earthworms. In a square of compost 4 ft by 4 ft, he can have 1000 earthworms. How many earthworms can he have if hi
charle [14.2K]
64,000 I believe. What I did was find the area so 4*4 =16. 1000/16 = 62.5 earthworms per square foot. So if the side is 8 times longer then 8*4= 32 feet per side and to find the area of that it's 32*32 = 1024 feet squared. So 62.5 * 1024 =64,000
6 0
3 years ago
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2/v + 2 = 9 solve for v
kenny6666 [7]
2/v+2=9
-2 -2
2/v=7
(2)2/v=7(2)

V=14
6 0
3 years ago
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