All categories

2 years ago

Sheila earns a 1.5% commission as a salesperson. She sold a bike for $200.

Mathematics

1 answer:

Hatshy [7]2 years ago

8 0

Answer:

q1) $3.00 q2)$197.00

Step-by-step explanation:

q1) 200 times 1.5% = $3

q2) 200 - 3 = $197

You might be interested in

Xsquared -5x= 2x-6 what is the solution

mote1985 [20]

Xsquared -5x= 2x-6
x^2 - 5x - 2x + 6 = 0
x^2 - 7x + 6 = 0
(x -6)(x-1) = 0
x-6 = 0, x = 6
x - 1 = 0, x = 1
answer
solutions
x = 1 and x =6

4 0

3 years ago

Read 2 more answers

The radius of a cone is decreasing at a constant rate of 7 inches per second, and the volume is decreasing at a rate of 948 cubi

inessss [21]

Answer:

The height of cone is decreasing at a rate of 0.085131 inch per second.

Step-by-step explanation:

We are given the following information in the question:

The radius of a cone is decreasing at a constant rate.

$\displaystyle\frac{dr}{dt} = -7\text{ inch per second}$

The volume is decreasing at a constant rate.

$\displaystyle\frac{dV}{dt} = -948\text{ cubic inch per second}$

Instant radius = 99 inch

Instant Volume = 525 cubic inches

We have to find the rate of change of height with respect to time.

Volume of cone =

$V = \displaystyle\frac{1}{3}\pi r^2 h$

Instant volume =

$525 = \displaystyle\frac{1}{3}\pi r^2h = \frac{1}{3}\pi (99)^2h\\\\\text{Instant heigth} = h = \frac{525\times 3}{\pi(99)^2}$

Differentiating with respect to t,

$\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)$

Putting all the values, we get,

$\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)\\\\-948 = \frac{1}{3}\pi\bigg(2(99)(-7)(\frac{525\times 3}{\pi(99)^2}) + (99)(99)\frac{dh}{dt}\bigg)\\\\\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi} = (99)^2\frac{dh}{dt}\\\\\frac{1}{(99)^2}\bigg(\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi}\bigg) = \frac{dh}{dt}\\\\\frac{dh}{dt} = -0.085131$

Thus, the height of cone is decreasing at a rate of 0.085131 inch per second.

3 0

2 years ago

What is the product for this question. Explain how if you can

Lyrx [107]

Answer:

Step-by-step explanation:

3 0

2 years ago

PQ is rotated 180 degrees clockwise about P. What are the coordinates of P' and Q'?

Salsk061 [2.6K]

The co ordinates of P' is (-7,-2) and Q' is (-16, -8)

Explanation

PQ is rotated 180 degrees clockwise about P. It means P and P' are the same points.

According to the graph, the coordinates of P is (-7, -2) and Q is (2, 4)

When PQ is rotated 180 degrees clockwise about P, then P or P' will be the mid-point of Q and Q'

Suppose, the co ordinate of Q' is (x, y)

Now according to the mid-point formula, the coordinate of P or P' will be: $(\frac{x+2}{2},\frac{y+4}{2})$ , which is actually at (-7, -2)

Thus.....

$\frac{x+2}{2}=-7\\ \\ x+2=-14\\ \\ x= -16\\ \\ and\\ \\ \frac{y+4}{2}= -2\\ \\ y+4= -4\\ \\ y= -8$

So, the co ordinates of P' is (-7,-2) and Q' is (-16, -8)

6 0

2 years ago

1. What is the transformed quadratic equation of 3x2 + 5x = 6 in the form of ax2 + bx + c = 0?

Murljashka [212]

Answer:

That will be;

3x^2 + 5x -6 = 0

Step-by-step explanation:

Here, we want to write 3x^2 + 5x = 6 in the form

ax^2 + bx + c = 0

That will be;

3x^2 + 5x -6 = 0

We can simply get it by bringing the value 6 from the right hand side of the equation to the left hand side of the equation

6 0

3 years ago