Question

36x^3 +27x^2=0 pls help me solve :/​

Answer 1

Answer:          36x^3 +27x^2 = 9x^2\left(4x+3\right)

Step-by-step explanation: apply exponent rule rewrite factor out common term plz enjoy

Answer 2

Answer:

$x = 0\; ,-\frac{3}{4}$

Step-by-step explanation:

$36x^3 + 27x^2 = 0$

• Take 9x² common from the expression on L.H.S.

$=> 9x^2(4x + 3) = 0$

Here, x will have 2 values :-

1) $9x^2(4x + 3) = 0$

• Divide both the sides by (4x + 3)

$=> \frac{9x^2(4x + 3)}{(4x+3)} = \frac{0}{4x+3}$

$=> 9x^2 = 0$

• Divide both the sides by 9x

$=> \frac{9x^2}{9x} = \frac{0}{9x}$

$=> x = 0$

2) $9x^2(4x + 3) = 0$

• Divide both the sides by 9x²

$=> \frac{9x^2(4x + 3)}{9x^2} = \frac{0}{9x^2}$

$=> 4x+3 = 0$

• Substract both the sides from 3

$=> 4x+3 -3 = 0 - 3$

$=> 4x=-3$

• Divide both the sides by 4

$=> \frac{4x}{4} = \frac{-3}{4}$

$=> x = -\frac{3}{4}$