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jasenka [17]
3 years ago
5

36x^3 +27x^2=0 pls help me solve :/​

Mathematics
2 answers:
Anettt [7]3 years ago
8 0

Answer:          36x^3 +27x^2 = 9x^2\left(4x+3\right)

Step-by-step explanation: apply exponent rule rewrite factor out common term plz enjoy

Tanzania [10]3 years ago
8 0

Answer:

x = 0\; ,-\frac{3}{4}

Step-by-step explanation:

36x^3 + 27x^2 = 0

  • Take 9x² common from the expression on L.H.S.

=> 9x^2(4x + 3) = 0

Here, x will have 2 values :-

1) 9x^2(4x + 3) = 0

  • Divide both the sides by (4x + 3)

=> \frac{9x^2(4x + 3)}{(4x+3)} = \frac{0}{4x+3}

=> 9x^2 = 0

  • Divide both the sides by 9x

=> \frac{9x^2}{9x} = \frac{0}{9x}

=> x = 0

2) 9x^2(4x + 3) = 0

  • Divide both the sides by 9x²

=> \frac{9x^2(4x + 3)}{9x^2} = \frac{0}{9x^2}

=> 4x+3 = 0

  • Substract both the sides from 3

=> 4x+3 -3 = 0 - 3

=> 4x=-3

  • Divide both the sides by 4

=> \frac{4x}{4} = \frac{-3}{4}

=> x = -\frac{3}{4}

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