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Ad libitum [116K]
3 years ago
8

A theater company has raised $810.75 by selling 15 floor seat tickets. Each ticket cost the same.

Mathematics
2 answers:
Goryan [66]3 years ago
4 0

Answer:

the other person is right

Step-by-step explanation:

ira [324]3 years ago
3 0

Answer:

Part A: 810.75/15=p

Part B: $54.05

Step-by-step explanation:

Part A: If the company has raised $810.75 by selling 15 tickets you have to divide the amount they have made by the amount of tickets they have sold.

Part B: 810.75 divided by 15 equals 54.05.

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45 C a b 7. If a=7 then the value of c is 7 14 C 9.9 3.5 8. If b= 9, then the value of a is A 9 B 18 6.4 D 9 If c= 12, then the
Naily [24]

Answer:

have u done answered it???

Step-by-step explanation:

4 0
3 years ago
Four less than the square of a number is 0​
marusya05 [52]

Answer:

± 2

Step-by-step explanation:

let the number be n , then

n² - 4 = 0 ( add 4 to both sides )

n² = 4 ( take square root of both sides )

n = ± \sqrt{4} = ± 2

The number is - 2 or 2

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3 years ago
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How do you get the area of quarter of a circle
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Find the circumference of the whole circle,divide by 4,and then add the radius twice.
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3 years ago
Question 3: In les Miserables Monsier, Thenardier, and Madame Thenardier are married and during act two, Cosette and Marius beco
Natasha2012 [34]
Answer: 14,515,200

Note: this is a single number (not an ordered triple or a collection of three different numbers) roughly equal to about 14.5 million if you round to the nearest hundred thousand.

----------------------------------------------

Explanation:

There are 13 people. Let's call them person A, person B, person C, ... all the way up to person M. The first four people are given who we'll call A through D. The rest (E through M) aren't really important since they aren't named. 

A = Monsier Thenardier
B = Madame Thenardier
C = Cosette
D = Marius
Peron's E through M = remaining 9 people

------------------

A and B must stick together. Because of this, we can consider "AB" as one "person".
So we go from 13 people to 13-2+1 = 12 "people". 

Likewise, C and D must stick together. We can consider "CD" as one "person". So we go from 12 "people" to 12-2+1 = 11 "people"

------------------

The question is now: how many ways can we arrange these 11 "people" around a circular table? The answer is (n-1)! ways where n = 11 in this case

So, (n-1)! = (11-1)! = 10! = 10*9*8*7*6*5*4*3*2*1 = 3,628,800

We're almost at the answer. We need to do two adjustments. 

First off, for any single permutation, there are two ways to arrange "AB". The first is "AB" itself and the second is the reverse of that "BA". So we will multiply 3,628,800 by 2 to get 2*3,628,800 = 7,257,600

Using similar logic for "CD", we double 7,257,600 to get 2*7,257,600 = 14,515,200

The final answer is 14,515,200


7 0
3 years ago
A flying cannonball’s height is described by formula y=−16t^2+300t. Find the highest point of its trajectory. In how many second
Yakvenalex [24]
<span>Highest point = 1406.25 Number of seconds = 9.375 We've been given the quadratic equation y = -16t^2 + 300t which describes a parabola. Since a parabola is a symmetric curve, the highest value will have a t value midway between its roots. So using the quadratic formula with A = -16, B = 300, C = 0. We get the roots of t = 0, and t = 18.75. The midpoint will be (0 + 18.75)/2 = 9.375 So let's calculate the height at t = 9.375. y = -16t^2 + 300t y = -16(9.375)^2 + 300(9.375) y = -16(87.890625) + 300(9.375) y = -1406.25 + 2812.5 y = 1406.25 So the highest point will be 1406.25 after 9.375 seconds. Let's verify that. I'll use the value of (9.375 + e) for the time and substitute that into the height equation and see what I get.' y = -16t^2 + 300t y = -16(9.375 + e)^2 + 300(9.375 + e) y = -16(87.890625 + 18.75e + e^2) + 300(9.375 + e) y = -1406.25 - 300e - 16e^2 + 2812.5 + 300e y = 1406.25 - 16e^2 Notice that the only term with e is -16e^2. Any non-zero value for e will cause that term to be negative and reduce the total value of the equation. Therefore any time value other than 9.375 will result in a lower height of the cannon ball. So 9.375 is the correct time and 1406.25 is the correct height.</span>
4 0
4 years ago
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