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3 years ago

Calculate the area of the shape below 7.6 cm 11 cm

Mathematics

1 answer:

frozen [14]3 years ago

4 0

Answer:

7.6 x 11 = 83.6

Ignore decimal points, multiply normally.

THEN consider the numbers after the decimal point, count them then place the decimal point in your final answer from the left to the right of the many times the numbers are after the decimal point.

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The area of the parallelogram is 936 sq ft what’s the height

Makovka662 [10]

Answer:

h = 24 ft

Step-by-step explanation:

A = 936 ft^2, b = 39 ft.

A = bh

Divide both sides by b:

h = A/b = 936 ft / 39 ft = 24 ft

5 0

3 years ago

4. How fast was a driver going if the car left skid marks that were 32 feet long on dry concrete? (The coefficient of friction i

Monica [59]

Answer:

$v_{o} \approx 31.247\,mph$

Step-by-step explanation:

The deceleration experimented by the car is the product of kinetic coefficient of friction and gravitational constant:

$a = \mu_{k}\cdot g$

$a = (1.02)\cdot \left(32.174\,\frac{ft}{s^{2}} \right)$

$a = 32.817\,\frac{ft}{s^{2}}$

The initial speed is computed from the following kinematic expression:

$v^{2} = v_{o}^{2} - 2\cdot a \cdot \Delta s$

$v_{o} = \sqrt{v^{2}+2\cdot a\cdot \Delta s}$

$v_{o} = \sqrt{\left(0\,\frac{ft}{s} \right)^{2}+2\cdot \left(32.817\,\frac{ft}{s^{2}} \right)\cdot (32\,ft)}$

$v_{o}\approx 45.829\,\frac{ft}{s}$

$v_{o} \approx 31.247\,mph$

8 0

3 years ago

243 log 3^4x = 48 , x=...

lilavasa [31]

243log(81x)=48
log(81x)=48÷243
log(81x)=16÷81
81x=10^(16÷81)
81x= 81sqaure root pf 10^16
divide by 81
x =.0194557

3 0

3 years ago

Fifty tickets are sold for a raffle.you buy four tickets and your friend buys three tickets.one ticket is randomly chosen as the

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there would be a 14 percent chance of you or your friend winning

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3 years ago

Read 2 more answers

What is f(x)=2x-1 if x=0

mrs_skeptik [129]

Answer:

$f=\frac{2x-1}{x}$

Step-by-step explanation:

3 0

3 years ago