If we take the Pythagorean identity identity sin^2 x + cos^2 x = 1 then
<span>(cos^2 x + sin^2 x) / (cot^2 x - csc^2 x)
The numerator becomes 1 since addition order matters not.
1 / </span>(cot^2 x - csc^2 x)
If we factor the denominator out a negative
1 / -(<span>csc^2 x - cot^2 x)
Consider </span><span>sin^2 x + cos^2 x = 1. Divide both sides by sin^2 x to get
1 + cot^2 x = csc^2 x
Subtract both sides by cot^2 x to get 1 = csc^2 x - cot^2 x.
Replace the denominator
1 / -(1) = -1
For cos</span>^2 θ / sin^2 θ + csc θ sin θ, we use cscθ = 1/sinθ and cosθ/sinθ = cotθ so
= cos^2 θ / sin^2 θ + 1
= cot^2 θ + 1
We use 1 + cot^2 <span>θ = csc^2 </span>θ to simplify this to
= csc^2 θ
Answers: -1
csc^2 θ
Answer: Domain: x = All Real Numbers (-∞, ∞)
Range: y ≤ 1 (-∞, 1]
<u>Step-by-step explanation:</u>
y = -2(x - 4)² + 1
The equation is in vertex form → vertex = (4, 1)
The leading coefficient is negative so it will be a max at y = 1
Range: y ≤ 1.
This is a polynomial so there are no restrictions on x.
Domain: x = All Real Numbers
Answer:
Step-by-step explanation:
These 2 angles are supplementary so we have
x+ 88 + x + 108 = 180
2x + 196 = 180
2c = -16
x = -8
the 2 angles are -8+88 and -8+108
that is 80 and 100.
1.07x is the sum of the equation
