In a right triangle, the square of both legs is equal to the length of hypotenuse squared. This is the Pythagorean theorem: a²+b²=c². For more graphical explanation, please refer to the attachment below.

Given

Leg a = 36 in

Leg b = 48 in

Hypotenuse c = 60 in

Solve

a² + b² = c²

(36)² + (48)² = 3600

(60)² = 3600

3600 = 3600

Therefore, the answer is YES

Hope this helps!! :)

Please let me know if you have any questions

6 0

3 years ago

61 = m + - 8 what would be m

Zigmanuir [339]

Answer:

m would be 69!

Step-by-step explanation:

61 = m - 8

61 + 8 = m - 8 + 8

69 = m

7 0

2 years ago

Read 2 more answers

Find the slope of the tangent line to the given polar curve at the point specified by the value of θ

MariettaO [177]

The given curve has equation

r(θ) = 9 + 8 cos(θ)

and its derivative is

dr/dθ = -8 sin(θ)

When θ = π/3, we have r (π/3) = 13, and dr/dθ (π/3) = -4√3.

Differentiate these with respect to θ :

dy/dθ = dr/dθ sin(θ) + r(θ) cos(θ)

dx/dθ = dr/dθ cos(θ) - r(θ) sin(θ)

In polar coordinates, we have

y(θ) = r(θ) sin(θ)

x(θ) = r(θ) cos(θ)

and when θ = π/3, we have y (π/3) = 13√3/2 and x (π/3) = 13/2.

The slope of the tangent line to the curve is dy/dx. By the chain rule,

dy/dx = dy/dθ • dθ/dx = (dy/dθ) / (dx/dθ)

dy/dx = (dr/dθ sin(θ) + r(θ) cos(θ)) / (dr/dθ cos(θ) - r(θ) sin(θ))

When θ = π/3, the slope is

dy/dx = (-4√3 sin(π/3) + 13 cos(π/3)) / (-4√3 cos(π/3) - 13 sin(π/3))

dy/dx = (-4√3 (√3/2) + 13 (1/2)) / (-4√3 (1/2) - 13 (√3/2))

dy/dx = - 1/(17√3)

So, the tangent line has slope -1/(17√3) and passes through (13/2, 13√3/2). Using the point-slope formula, its equation is

y - 13√3/2 = -1/(17√3) (x - 13/2)

y = -(x - 338)/(17√3)

4 0

2 years ago