<span>Ka = [H+][PAc-] / [PAcH]
[H+] = 10^-2.68 = 0.00209M = [PAc-]
[PAcH] = 0.085 = 0.00209 = 0.083
Ka = (.00209)(.00209) / (0.083) = Answer Here.</span>
Answer:
Products
Explanation:
In an endothermic reaction, energy is taken in. This means that the absorption of energy favours the forward reaction.
Hence for a process; A + B----> C, if energy must be added for the equilibrium to shift towards the right and more of C is produced, then the reaction is endothermic.
The balanced equation for the reaction is as follows;
2Fe + 3S ---> Fe₂S₃
molar ratio of Fe to Fe₂S₃ is 2:1
mass of Fe₂S₃ to be produced is - 96 g
therefore number of moles of Fe₂S₃ to be produced is - 96 g / 208 g/mol
number of Fe₂S₃ moles = 0.46 mol
according to the molar ratio
when 2 mol of Fe reacts with 3 mol of sulfur then 1 mol of Fe₂S₃ is produced
that for 1 mol of Fe₂S₃ to be produced - 2 mol of Fe should react
therefore for 0.46 mol of Fe₂S₃ to be produced - 2 x 0.46 = 0.92 mol of Fe is required
mass of Fe required - 0.92 mol x 56 g/mol = 51.5 g
mass of Fe required is - 51.5 g
Answer:
See below.
Step-by-step explanation:
Ethers react with HI at high temperature to produce an alky halide and an alcohol.
R-OR' + HI ⟶ R-I + H-OR'
<em>Benzylic ethers</em> react by an Sₙ1 mechanism by forming the stable benzyl cation.
- PhCH₂-OR + HI ⟶ PhCH₂-O⁺(H)R + I⁻ Protonation of the ether
- PhCH₂-O⁺(H)R ⟶ PhCH₂⁺ + HOR Sₙ1 ionization of oxonium ion
- PhCH₂⁺ + I⁻ ⟶ PhCH₂-I Nucleophilic attack by I⁻
If there is excess HI, the alcohol formed in Step 2 is also converted to an alkyl iodide:
ROH +HI ⟶ R-I + H-OH
Thus, benzyl ethyl ether reacts to form benzyl iodide (a) and ethanol (b).
The ethanol reacts with excess HI in an Sₙ2 reaction to form ethyl iodide (c).
Answer:
Dana filtered the sample and larger granules of the sample were left behind.
Explanation:
If a substance is pure, it will have a uniform composition throughout. It will not separate into particles of various sizes.
One of the characteristics of pure substances is that they are homogeneous. A mixture is definitely made up of particles of various sizes.
Since the particles was filtered and larger granules were left behind, the sample has been separated by a physical method (filtration). Only a mixture can be separated by physical methods. It is not a pure substance.