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3 years ago

What type of wave DOES NOT require a medium? Electromagnetic wave or Mechanical wave?

Chemistry

2 answers:

Genrish500 [490]3 years ago

7 0

Answer;

Electromagnetic wave

Explanation;

Electromagnetic waves are waves that do not require a material medium for transmission, they include, x-rays, gamma rays, visible light etc.

Anarel [89]3 years ago

7 0

Electromagnetic Waves

Explanation:

Electromagnetic waves do not require a medium to propagate whereas mechanical wave does.

Example: Sound wave is mechanical wave. It needs a medium to transfer energy from one place to another.

And, X-rays. These are electromagnetic waves & these transfer energy via electric & magnetic fields.

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If 125 mL of a 1.1 M glucose solution is diluted to 500.0 mL , what is the molarity of the diluted solution? Express your answer

Juli2301 [7.4K]

Answer:

0.28M

Explanation:

From the question given, we obtained the following information:

C1 = 1.1 M

V1 = 125mL

V2 = 500mL

C2 =?

Using the dilution formula C1V1 = C2V2, we can easily find the molarity of the diluted solution as follows:

C1V1 = C2V2

1.1 x 125 = C2 x 500

Divide both side by 500

C2 = (1.1 x 125)/500 =

C2 = 0.28M

3 0

3 years ago

sam records the mass of his evaporating dish as 8.365 g. he records the mass of the evaporating dish and the sample of hydrate a

guapka [62]

0.2701 moles of water were evaporated from the sample by the heating process

Mass of evaporating dish = 8.365 g

mass of dish + hydrate = 18.597 g

mass of hydrate = (mass of dish + hydrate) - mass of dish

hydrate = 18.597 - 8.365 = 10.232 g

Mass of dehydrated material = (mass of dish + dehydrate ) - mass of dish

dehydrated material = 18.735 - 8.365 = 5.37 g

Mass of water evaporated = hydrate - dehydrate

mass of water = 10.232 - 5.37 = 4.862 g

Molar mass of water = 18 gm/mol

no. of moles of water evaporated = mass / molecular mass

moles = 4.862/18 = 0.2701 moles

To learn more about mole click here:

brainly.com/question/29367909

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7 0

1 year ago

What mass of hcl gas must be added to 1.00 l of a buffer solution that contains [aceticacid]=2.0m and [acetate]=1.0m in order to

Paraphin [41]

PH of acidic buffer = pKa + log [CH₃COONa - HCl] / [CH₃COOH + HCl]
pKa of CH₃COOH = 4.74
Concentration of acetic acid in buffer = 2.0 M
Concentration of sodium acetate = 1.0 M
Concentration of HCl must add = x
pH = 4.74 + log (1-x) / (2+x) = 4.11
x = concentration of HCl must be added = 0.43 M
number of moles of HCl = M * V = 0.43 * 1 = 0.43 mol
mass of HCl must be added = 0.43 * 36.5 = 15.7 g

3 0

4 years ago

I NEED ANSWER ASAP What are some examples of an unbalanced force?

garik1379 [7]

A adult pushing a car and a child pushing a car. Are two unbalanced forces

6 0

4 years ago

How many Liters of a 4.5 M HCL solution can be prepared by using 250.0 mL of a 12.0 M HCl solution?

netineya [11]

Answer:

0.667 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 250 mL

Initial concentration (C₁) = 12 M

Final concentration (C₂) = 4.5 M

Final volume (V₂) =?

The final volume of the solution can be obtained by using the dilution formula as illustrated below:

C₁V₁ = C₂V₂

12 × 250 = 4.5 × V₂

3000 = 4.5 × V₂

Divide both side by 4.5

V₂ = 3000 / 4.5

V₂ = 667 mL

Finally, we shall convert 667 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

667 mL = 667 mL × 1 L / 1000 mL

667 mL = 0.667 L

Thus, the volume of the solution prepared is 0.667 L

3 0

3 years ago