The integrated rate law for a second-order reaction is given by:
where, [A]t= the concentration of A at time t,
[A]0= the concentration of A at time t=0
<span>k =</span> the rate constant for the reaction
<u>Given</u>: [A]0= 4 M, k = 0.0265 m–1min–1 and t = 180.0 min
Hence,
<span> = 4.858</span>
<span><span><span>Therefore, [A]</span>t</span>= 0.2058 M.</span>
<span>
</span>
<span>Answer: C</span>oncentration of A, after 180 min, is 0.2058 M
Answer:
Following are the responses to the given question:
Explanation:
Since HN03 is an oxidation substance D-ribose u.ith oxidized to form in rubric acid Ribose is chiral, but rubric acid is achiral because of its symmetry mirror level, Hence no infrared roster in the sample holder is observed.
Please find the attached file.
D-Arabinose, on either hand, gives optical aldaric acid with such a net optical rotation observed inside the polarimeter for diagnosis with HN03.
Answer:
Explanation:
(a) Balanced reaction of gallium with oxygen is as follows:
(b)
Multiply the carbon dioxide by 6 to balance carbon as follows:
After that multiply H2O by 7 to balance hydrogen as follows:
Finally balance oxygen by multiplying O2 by 19/2. Therefore, balanced reaction is as follows:
(c)
first balance calcium, by multiply by 3 as follows:
After that balance phosphorous by multiplying by 2 as follows:
Finally balance Na by multiplying NaCl by 6. Therefore, balance reaction is as follows: