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worty [1.4K]
3 years ago
7

F(x)=x+6 and g(x)=a-2 then find f(6)+g(4)

Mathematics
1 answer:
3241004551 [841]3 years ago
6 0
F(6) = 6 + 6 = 12
g(4) = 4 - 2 = 2
12 + 2 = 14
The answer is 14
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Find the constant of variation for the relation and use it to write an equation for the statement. Then solve the equation.
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Answer: option d.

Step-by-step explanation:

If <em>y </em>varies directly as <em>x</em> and <em>z</em>, the form of the equation is:

y=kxz

Where<em> k</em> is the constant of variation.

If y=4 when x=6 and z=1 then substitute these values into the expression and solve for <em>k:</em>

4=k(6)(1)\\4=6k\\k=\frac{4}{6}\\\\k=\frac{2}{3}

<em> </em>Substitute the value of <em>k</em>  into the expression. Then, the equation is:

y=\frac{2}{3}xz

To find the value of <em>y </em>when x=7 and z=4, you must substute these values into the equation. Therefore you obtain:

y=k=\frac{2}{3}(7)(4)

y(7,4)=\frac{56}{3}

<em> </em>

5 0
2 years ago
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solve the systems of linear equations by graphing y=-5/2x-7 x+2y=4 what is the solution to the system of linear equations A. (-4
Sati [7]
The appropriate choice is
  A. (-4.5, 4.25)

3 0
3 years ago
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What is the company’s quick Ratio?
ArbitrLikvidat [17]

Answer:

c.

Step-by-step explanation:

8 0
2 years ago
Use​ Newton's method to find an approximate solution of ln(x)=10-x. Start with x_0 =9 and find x_2 .
vova2212 [387]

Answer:

x₂ = 7.9156

Step-by-step explanation:

Given the function  ln(x)=10-x with initial value x₀ = 9, we are to find the second approximation value x₂ using the Newton's method. According to Newtons method xₙ₊₁ = xₙ -  f(xₙ)/f'(xₙ)

If f(x) = ln(x)+x-10

f'(x) = 1/x + 1

f(9) = ln9+9-10

f(9) = ln9- 1

f(9) = 2.1972 - 1

f(9) = 1.1972

f'(9) = 1/9 + 1

f'(9) = 10/9

f'(9) = 1.1111

x₁ = x₀ -  f(x₀)/f'(x₀)

x₁ = 9 -  1.1972/1.1111

x₁  = 9 - 1.0775

x₁  = 7.9225

x₂ = x₁ -  f(x₁)/f'(x₁)

x₂ = 7.9225 -  f(7.9225)/f'(7.9225)

f(7.9225) = ln7.9225 + 7.9225 -10

f(7.9225) = 2.0697 + 7.9225 -10

f(7.9225) = 0.0078

f'(7.9225) = 1/7.9225 + 1

f'(7.9225) = 0.1262+1

f'(7.9225) = 1.1262

x₂ = 7.9225 - 0.0078/1.1262

x₂ = 7.9225 - 0.006926

x₂ = 7.9156

<em>Hence the approximate value of x₂ is 7.9156</em>

7 0
3 years ago
Pls help this should be the last thing
Lelu [443]

Answer:

1436 i believe

Step-by-step explanation:

7 0
2 years ago
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