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Answer:a) Probability P(exactly 2 bulbs rated 13watts)= 0.22
b) Probability(each bulb different rating)
= 0.24
Step-by-step explanation:
There are 6 13watts bulbs
8 18watts bulbs
4 23watts bulbs
Total bulbs = 18
a) Probability that all 3 bulbs are 18watts
Number of ways of pulling 3 bulbs = 18!/(3!×15!) = (6.4×10^15)/7.846×10^12) = 815 ways
Different ways of pulling 13watts bulbs out of 6 = 6!/(2!×4!)= 720/48=15ways
Different ways of pulling non 13 watts bulbs= 12!/(1!×11!) = 479,001,600/ 39,916,800 = 12
Number of ways total= 15×12=180waya
Therefore P(exactly 2 bulbs rated 13watts)= 180/815 =0.22
b) Probability P( all 3 bulbs are 1 from each rating)
Ways of pulling 3bulbs bulb each from 3 ratings are 4× 5 × 8= 192ways
Probability = 192/815 =0.24
Pile Y has the greater mean number of pages per book because it is 5 books less than pile W.
<h3>How to calculate greater mean number of pages?</h3>
From the complete information, we can deduce that the number of each pile of book is given as follows:
<u>For pile W;</u>
Red books = 10 × 5 = 50 red books.
Blue books = 5 × 5 = 25 blue books.
Therefore, total books in pile W = 50 + 25 = 75 books.
Mathematically, the mean for each pile can be calculated by using the following formula:
Mean = [F(x)]/n
Mean = 75/10
Mean = 7.5.
<u>For pile Y;</u>
Red books = 10 × 5 = 50 red books.
Mean = [F(x)]/n
Mean = 50/5
Mean = 10.
In conclusion, pile Y has the greater mean number of pages per book because it is 5 books less than pile W.
Read more on mean here: brainly.com/question/9550536
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