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natita [175]
3 years ago
11

Twelve cows produce 224,988 pounds of milk. Find the unit rate in pounds per cow.

Mathematics
1 answer:
12345 [234]3 years ago
3 0
Well, if 224,988 pounds of milk is produced by 12 cows, if i divide 224,988 by 12 i get the pounds per 1 cow. Consider it set up in this ratio.

224,988pounds/12 cows = xpounds/1 cow

Then you would solve for x.

Helpful? =)
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a child should no longer play in the kid zone area when they reach 4'4" tall joe is 54" tall is he allowed to play in the kid zo
Andreyy89

Answer: No.

Step-by-step explanation: Joe is 4'6" tall. Convert 54" to feet by dividing by 12. 54/12=4.5. Half of a foot is 6 inches.

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Ksivusya [100]

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Step-by-step explanation:

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3 years ago
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Select the best answer.<br><br> tan x tan x/2=
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4 0
3 years ago
Evaluate √x^2 − y^2 when x^2 =33 and y^2 =15
Andre45 [30]

Answer:

3√2

Step-by-step explanation:

In this question, we are asked to get the value of √ ( x²-y² ), while the value of x² and y² are given to be 33 and 15 respectively.

Hence, x² =33 and y² = 15.  

Putting the values of x² and y² in the above expression we get,

√ ( x²-y² ) = √ ( 33-15) = √18 =3√2. (Answer)

3 0
2 years ago
How do measurements of time differ for events in a frame of reference that moves at 50% of the speed of light relative to us? At
ZanzabumX [31]

Answer with explanation:

Relation between Speed , Distance and time

Distance =Speed × Time

→It means Speed is inversely Proportional to time.

As distance will remain constant , in that frame of reference

If speed of light in a Medium

                              =s=3 \times 10^8 \frac{\text{meter}}{\text{second}}

Then, time taken to cross the medium = t seconds or hours or another unit of time.

Now, If speed of light is 50% of the speed of light relative to us

    That is Speed of light in another medium

                 =w=\frac{50}{100} \times 3 \times 10^8\\\\=1.5 \times 10^8 \frac{\text{meter}}{\text{second}}

Then, time taken to cross the medium = 2t seconds or hours or another unit of time.

Using Unitary Method

  \rightarrow v_{1}\times t_{1}=v_{2} \times t_{2}\\\\1.\rightarrow 3 \times 10^8 \times t=\frac{50}{100} \times 3 \times 10^8 \times t_{1}\\\\t_{1}=2t\\\\2.\rightarrow 3 \times 10^8 \times t=\frac{99.5}{100} \times 3 \times 10^8 \times t_{2}\\\\t_{2}=\frac{1000t}{995}\\\\t_{2}=\frac{200t}{199}

             

7 0
3 years ago
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