All categories

2 years ago

A chef has 6 jars of spices. How many ways can he line up the jars on his kitchen shelf? Show your work.

Mathematics

2 answers:

tia_tia [17]2 years ago

8 0

He can line them up in 36 different ways since 6 times 6 is 36

neonofarm [45]2 years ago

3 0

6*6=36. he can line the jars pu 36 diff ways.

You might be interested in

Solve 12^x^2+5x-4 = 12^2x+6

faust18 [17]

The solutions for ‘x’ are 2 and -5

Step-by-step explanation:

Given equation:

$12^{x^{2}+5 x-4}=12^{2 x+6}$

Since the base on both sides as ‘12’ are the same, we can write it as

$x^{2}+5 x-4=2 x+6$

$x^{2}+5 x-2 x-4-6=0$

$x^{2}+3 x-10=0$

Often, the value of x is easiest to solve by $a x^{2}+b x+c=0$ by factoring a square factor, setting each factor to zero, and then isolating each factor. Whereas sometimes the equation is too awkward or doesn't matter at all, or you just don't feel like factoring.

The Quadratic Formula: For $a x^{2}+b x+c=0$ , the values of x which are the solutions of the equation are given by:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Where, a = 1, b = 3 and c = -10

$x=\frac{-3 \pm \sqrt{(-3)^{2}-4(1)(-10)}}{2(1)}$

$x=\frac{-3 \pm \sqrt{9+40}}{2}$

$x=\frac{-3 \pm \sqrt{49}}{2}=\frac{-3 \pm 7}{2}$

So, the solutions for ‘x’ are

$x=\frac{-3+7}{2}=\frac{4}{2}=2$

$x=\frac{-3-7}{2}=\frac{-10}{2}=-5$

The solutions for ‘x’ are 2 and -5

6 0

2 years ago

Read 2 more answers

Solve 3x + k = c for x

olasank [31]

Here we are given the equation 3x+k =c

Here in order to solve for x , first let us bring k to the right side.

k is in addition on the left , so when we bring it to the right it gets subtracted

$3x=c-k$

now we have to isolate x on the left side , 3 is in multiplication with x , so when we bring it to the right side we divide by 3

Answer: $x=\frac{(c-k)}{3}$

7 0

3 years ago

Read 2 more answers

Dose anyone know the answers to this? I'm taking a test and cant find the answer

Andrews [41]

I’m not sure but I think
F (2, -1)
G (1, -3)
H (-3, -1)

4 0

2 years ago

Colonization specifically refers to the multiplication of a pathogen on or within a host. True or False

Deffense [45]

Answer:

false

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Please help!!! Simplify in standard form. (2x5+x3−3x4−x+8)−(7x5+2x4−12+6x−5x3+x2)

Ilia_Sergeevich [38]

(2x^5+x^3−3x^4−x+8)−(7x^5+2x^4−12+6x−5x^3+x^2)
= 2x^5 − 3x^4 + x^3 −x + 8 − 7x^5 - 2x^4 + 5x^3 − x^2 − 6x + 12
= − 5x^5 − 5x^4 + 6x^3 − x^2 − 7x + 20

hope it helps

7 0

3 years ago