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alina1380 [7]
3 years ago
14

GEOMETRY Holly can make an open-topped box out of a square piece of cardboard by cutting 3-inch squares from the corners and fol

ding up the sides to meet. The volume of the resulting box is V = 3x^ 2 – 36x + 108, where x is the original length and width of the cardboard.
Factor the polynomial expression from the volume equation.

HINT: look for a GCF first!
Mathematics
1 answer:
cluponka [151]3 years ago
3 0

Answer:

V(x)=3(x-6)(x-6)

Step-by-step explanation:

<u>Polynomial Factoring</u>

The volume of a cardboard box is expressed as:

V(x)=3x^2-36x+108

It's required to factor that expression.

First, factor out 3:

V(x)=3(x^2-12x+36)

The expression in parentheses is a perfect square:

\boxed{V(x)=3(x-6)(x-6)}

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A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot
ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box  is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = (x\times x)

                               =x^2

The volume of the box  is = area of the base × height

                                           =x^2h

Therefore,

x^2h=272

\Rightarrow h=\frac{272}{x^2}

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

=20x^2 cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

=10x^2 cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

=4xh\times 1.5 cents

=6xh cents

Total cost = (20x^2+10x^2+6xh)

                =30x^2+6xh

Let

C=30x^2+6xh

Putting the value of h

C=30x^2+6x\times \frac{272}{x^2}

\Rightarrow C=30x^2+\frac{1632}{x}

Differentiating with respect to x

C'=60x-\frac{1632}{x^2}

Again differentiating with respect to x

C''=60+\frac{3264}{x^3}

Now set C'=0

60x-\frac{1632}{x^2}=0

\Rightarrow 60x=\frac{1632}{x^2}

\Rightarrow x^3=\frac{1632}{60}

\Rightarrow x\approx 3

Now C''|_{x=3}=60+\frac{3264}{3^3}>0

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is =\frac{272}{3^2}

                                          =30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0
3 years ago
Which of the fractions below is closest to one?
Ber [7]

Answer:

A

Step-by-step explanation:

1/4 is 3/4 away from being 4/4 = 1.

6 0
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The answer is nonlinear. It goes in a sharp downward curve, whereas a linear function is a straight line.

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3 years ago
Answer this quickly please!
rodikova [14]

Answer:

\bar v = 60\,mph

Step-by-step explanation:

The distance travelled by Lisa in the first four hours of her trip is:

\Delta s = \left(50\,mph)\cdot (4\,h)

\Delta s = 200\,mi

The distance remaining and her average speed are, respectively:

\Delta s_{R} = 440\,mi - 200\,mi

\Delta s_{R} = 240\,mi

\bar v = \frac{240\,mi}{4\,h}

\bar v = 60\,mph

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❤️❤️__pvx-biov-wdv___❤️❤️truth an dare❤️can any girl from Australia join and play with me?​
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Step-by-step explanation:

not possible, but thanks for the points..!

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