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alina1380 [7]
2 years ago
14

GEOMETRY Holly can make an open-topped box out of a square piece of cardboard by cutting 3-inch squares from the corners and fol

ding up the sides to meet. The volume of the resulting box is V = 3x^ 2 – 36x + 108, where x is the original length and width of the cardboard.
Factor the polynomial expression from the volume equation.

HINT: look for a GCF first!
Mathematics
1 answer:
cluponka [151]2 years ago
3 0

Answer:

V(x)=3(x-6)(x-6)

Step-by-step explanation:

<u>Polynomial Factoring</u>

The volume of a cardboard box is expressed as:

V(x)=3x^2-36x+108

It's required to factor that expression.

First, factor out 3:

V(x)=3(x^2-12x+36)

The expression in parentheses is a perfect square:

\boxed{V(x)=3(x-6)(x-6)}

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22 - 10 + (18 ÷ 3) =
juin [17]
Follow PEMDAS (parenthesis- exponents (& roots) - multiplication - division - addition - subtraction)


18/3 = 6

22 - 10 = 12

12 + 6 = 18

18 is your answer

hope this helps
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3 years ago
A + 4 = 6, when a = 2. true false open
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True
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3 years ago
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help me with the Quadratic equation.... x2+ (p - 5) x + 2q = 0 has the roots −3 and 6. Find the value of P and the value of q.​
nirvana33 [79]

Step-by-step explanation:

The quadratic equation is x² + (p - 5)x + 2q = 0.

By Vieta's Formula,

we have SOR = -b/a and POR = c/a.

=> (-3) + (6) = -(p - 5) and (-3)(6) = 2q.

=> 3 = 5 - p and -18 = 2q

Hence, p = 2 and q = -9.

Alternate Method:

We have (x + 3) and (x - 6) as factors of the quadratic equation x² + (p - 5)x + 2q = 0.

=> (x + 3)(x - 6) = x² - 3x - 18.

By Comparing Coefficients,

(p - 5) = -3 and 2q = 18.

Hence p = 2 and q = -9.

8 0
3 years ago
2 +4 +5+400+888+953<br> what is it
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3 years ago
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A fair die is rolled 5 times. What is the probability that a 3 is obtained on at least one of the rolls? Round your answer to th
Lerok [7]

Answer:

0.200

Step-by-step explanation:

The probability of obtaining a 3, in one roll of a fair die is 1/6.

Now, we have 5 rolls.

We now want to know the probability of a 3 showing up in at least one of the rolls.

This simply mean, we add the probabilities of three showing one time plus probability of three showing in 2 of the rolls e.t.c

This means we can have 3 showing up to 5 times.

We add the probabilities as follows:

(1/6) + (1/6)^2 + (1/6)^3 + (1/6)^4 + (1/6)^5 = 0.199974 = 0.200

3 0
3 years ago
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