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Vlad [161]
3 years ago
13

Solve the system by graphing. It is REQUIRED to check your solution. Show work for this problem on your work page.

Mathematics
2 answers:
Hunter-Best [27]3 years ago
6 0

Answer:

y=x-1

y=-2x-4

although I cant summon a graph for this one, I can give cords

for first graph (-2,-3),(-1,-2),(0,-1), (1,0),(2,1)

For second graph the slope is down 2 over 1, and begins at (0,-4).

(-2,0)(-1,-2),(0,-4),(1,-6),(2,-8)

Rashid [163]3 years ago
5 0

Let's solve for x.

y=x−1

Step 1: Flip the equation.

x−1=y

Step 2: Add 1 to both sides.

x−1+1=y+1

x=y+1

Answer:

x=y+1

---------------------------------

Let's solve for x.

y=−2x−4

Step 1: Flip the equation.

−2x−4=y

Step 2: Add 4 to both sides.

−2x−4+4=y+4

−2x=y+4

Step 3: Divide both sides by -2.

−2x

−2

=

y+4

−2

x=

−1

2

y−2

Answer:

x=

−1

2

y−2

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<span>67/100 as a decimal.


Divide numerator by denominator. Answer = decimal form.

67/100
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Find the critical numbers of the function. (Enter your answers as a comma-separated list. Use n to denote any arbitrary integer
lyudmila [28]

If

f(\theta)=10\cos\theta+5\sin^2\theta

then the derivative is

f'(\theta)=-10\sin\theta+10\sin\theta\cos\theta

Critical points occur where f'(\theta)=0. This happens for

-10\sin\theta+10\sin\theta\cos\theta=0

-10\sin\theta(1-\cos\theta)=0

\implies-10\sin\theta=0\text{ or }1-\cos\theta=0

In the first case, we find

-10\sin\theta=0\implies\sin\theta=0\implies\theta=n\pi

In the second,

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3/4 or 9/12

Step-by-step explanation:

Since there are 12 movies in total. The possible chance of picking a drama movie is a 1 out of 4 chance (3/12 = 1/4), the possible of picking a movie without a drama is a 3 out of 4 chance (9/12 = 3/4)

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f(x) = 3 cos(x) 0 ≤ x ≤ 3π/4 evaluate the Riemann sum with n = 6, taking the sample points to be left endpoints. (Round your ans
Kruka [31]

Answer:

\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx\approx 3.099558

Step-by-step explanation:

We want to find the Riemann sum for \int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx with n = 6, using left endpoints.

The Left Riemann Sum uses the left endpoints of a sub-interval:

\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f(x_0)+f(x_1)+2f(x_2)+...+f(x_{n-2})+f(x_{n-1})\right)

where \Delta{x}=\frac{b-a}{n}.

Step 1: Find \Delta{x}

We have that a=0, b=\frac{3\pi }{4}, n=6

Therefore, \Delta{x}=\frac{\frac{3 \pi}{4}-0}{6}=\frac{\pi}{8}

Step 2: Divide the interval \left[0,\frac{3 \pi}{4}\right] into n = 6 sub-intervals of length \Delta{x}=\frac{\pi}{8}

a=\left[0, \frac{\pi}{8}\right], \left[\frac{\pi}{8}, \frac{\pi}{4}\right], \left[\frac{\pi}{4}, \frac{3 \pi}{8}\right], \left[\frac{3 \pi}{8}, \frac{\pi}{2}\right], \left[\frac{\pi}{2}, \frac{5 \pi}{8}\right], \left[\frac{5 \pi}{8}, \frac{3 \pi}{4}\right]=b

Step 3: Evaluate the function at the left endpoints

f\left(x_{0}\right)=f(a)=f\left(0\right)=3=3

f\left(x_{1}\right)=f\left(\frac{\pi}{8}\right)=3 \sqrt{\frac{\sqrt{2}}{4} + \frac{1}{2}}=2.77163859753386

f\left(x_{2}\right)=f\left(\frac{\pi}{4}\right)=\frac{3 \sqrt{2}}{2}=2.12132034355964

f\left(x_{3}\right)=f\left(\frac{3 \pi}{8}\right)=3 \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}}=1.14805029709527

f\left(x_{4}\right)=f\left(\frac{\pi}{2}\right)=0=0

f\left(x_{5}\right)=f\left(\frac{5 \pi}{8}\right)=- 3 \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}}=-1.14805029709527

Step 4: Apply the Left Riemann Sum formula

\frac{\pi}{8}(3+2.77163859753386+2.12132034355964+1.14805029709527+0-1.14805029709527)=3.09955772805315

\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx\approx 3.099558

5 0
3 years ago
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