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nadya68 [22]
3 years ago
6

The sum of the cube of a number and 12

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
3 0
Let the "number" be n.

The expression would be n^3+12
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Tickets to a play cost $4 in advance and $5 at the door. The theater club president wants to raise at least $400 from the ticket
tresset_1 [31]

Answer:

x≥48

Step-by-step explanation:

4×40 = 160

400-160 = 240

240÷5 = 48

6 0
3 years ago
If there are 19 successful outcomes in a sample with a size of 25, what is the sample proportion
alexandr1967 [171]

Answer: the answer is .76


Step-by-step explanation:


5 0
3 years ago
The range of the function defined as y = 5x is
snow_tiger [21]
The answer, i believe, is B
8 0
2 years ago
Forty percent of households say they would feel secure if they had $50,000 in savings. you randomly select 8 households and ask
Kay [80]

Answer:

Let X be the event of feeling secure after saving $50,000,

Given,

The probability of feeling secure after saving $50,000, p = 40 % = 0.4,

So, the probability of not  feeling secure after saving $50,000, q = 1 - p = 0.6,

Since, the binomial distribution formula,

P(x=r)=^nC_r p^r q^{n-r}

Where, ^nC_r=\frac{n!}{r!(n-r)!}

If 8 households choose randomly,

That is, n = 8

(a) the probability of the number that say they would feel secure is exactly 5

P(X=5)=^8C_5 (0.4)^5 (0.6)^{8-5}

=56(0.4)^5 (0.6)^3

=0.12386304

(b) the probability of the number that say they would feel secure is more than five

P(X>5) = P(X=6)+ P(X=7) + P(X=8)

=^8C_6 (0.4)^6 (0.6)^{8-6}+^8C_7 (0.4)^7 (0.6)^{8-7}+^8C_8 (0.4)^8 (0.6)^{8-8}

=28(0.4)^6 (0.6)^2 +8(0.4)^7(0.6)+(0.4)^8

=0.04980736

(c) the probability of the number that say they would feel secure is at most five

P(X\leq 5) = P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5)

=^8C_0 (0.4)^0(0.6)^{8-0}+^8C_1(0.4)^1(0.6)^{8-1}+^8C_2 (0.4)^2 (0.6)^{8-2}+8C_3 (0.4)^3 (0.6)^{8-3}+8C_4 (0.4)^4 (0.6)^{8-4}+8C_5(0.4)^5 (0.6)^{8-5}

=0.6^8+8(0.4)(0.6)^7+28(0.4)^2(0.6)^6+56(0.4)^3(0.6)^5+70(0.4)^4(0.6)^4+56(0.4)^5(0.6)^3

=0.95019264

8 0
3 years ago
Find the value of x from the equation
Jobisdone [24]

\dfrac{8^{3x}}{2^{10}}=\dfrac{4^{2x}}{16} \\\dfrac{2^{3(3x)}}{2^{10}}=\dfrac{4^{2x}}{4^2} \\2^{9x-10}=4^{2x-2} \\2^{9x-10}=2^{2(2x-2)} \\2^{9x-10}=2^{4x-4} \\9x-10=4x-4 \\5x-6=0 \\5x=6 \\\boxed{x=\dfrac{6}{5}}

Hope this helps.

r3t40

3 0
3 years ago
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