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cricket20 [7]
2 years ago
14

Pleaseeeeeeee helppppppppppppppppppppppppppppp

Mathematics
1 answer:
ankoles [38]2 years ago
8 0
The first two are true and the last one is false
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Y=2x-2 and 4x+2y=12. solve the equation PLEASE SHOW WORK​
diamong [38]
<h3>The solution as an ordered pair is (x,y) = (2,2)</h3><h3>x = 2 and y = 2 pair up together.</h3>

===============================

Work Shown:

4x+2y = 12

4x+2( y ) = 12

4x+2( 2x-2 ) = 12 ... replace y with 2x-2

4x+2( 2x ) + 2( -2 ) = 12 ... distribution rule

4x+4x-4 = 12

8x-4 = 12

8x-4+4 = 12+4 ... add 4 to both sides

8x = 16

8x/8 = 16/8 ... divide both sides by 8

x = 2 is the first part of the answer

Use x = 2 to find y

y = 2x-2

y = 2(2)-2 ... replace x with 2

y = 4-2

y = 2 is the second part of the answer

8 0
3 years ago
Read 2 more answers
-5 -(15y - 1) = 2(7y - 16) -y
Luda [366]
-5-(15y-1) = 2(7y-16) - y  // question
-5-15y+1 = 14y-32-y  // distribute
-15y - 4 = 13y - 32    // subtract
-28y = -28  // divide
y = 1
7 0
3 years ago
the width of a rectangle is 5 meters less than it’s length. The area of the rectangle is 84m^2. Find the length and width of the
larisa [96]
16.8m is the length and 5m is width
3 0
3 years ago
In a toy​ store, the ratio of the number of dolls to the number of teddy bears is . If the store has 240​ dolls, how many teddy
forsale [732]

Answer:

<u>So, the way a ratio works is </u><u>"for every 1 of this, we have 4 of this"</u><u> for example. (the ratio I just described would be 1:4.) </u>

<u />

I believe I've seen this question before. If the ratio of dolls to teddy bears is 9:3 then for every 9 dolls you have 3 teddy bears.

So, since we have 240 dolls and a 9:3 ratio to teddy bears, all we have to do is take how many dolls we have (240) and divide it by 3 to see how many teddy bears we have.

So:

240 ÷ 3  = 80

If your ratio is 9:3, then 80 is your answer.

<u>Hope this helps and have a nice day!</u>

<u></u>

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%20%5Csf%20%5Chuge%7B%20question%20%5Chookleftarrow%7D" id="TexFormula1" title=" \sf \huge
BabaBlast [244]

\underline{\bf{Given \:equation:-}}

\\ \sf{:}\dashrightarrow ax^2+by+c=0

\sf Let\:roots\;of\:the\: equation\:be\:\alpha\:and\beta.

\sf We\:know,

\boxed{\sf sum\:of\:roots=\alpha+\beta=\dfrac{-b}{a}}

\boxed{\sf Product\:of\:roots=\alpha\beta=\dfrac{c}{a}}

\underline{\large{\bf Identities\:used:-}}

\boxed{\sf (a+b)^2=a^2+2ab+b^2}

\boxed{\sf (√a)^2=a}

\boxed{\sf \sqrt{a}\sqrt{b}=\sqrt{ab}}

\boxed{\sf \sqrt{\sqrt{a}}=a}

\underline{\bf Final\: Solution:-}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}

\bull\sf Apply\: Squares

\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2= (\sqrt{\alpha})^2+2\sqrt{\alpha}\sqrt{\beta}+(\sqrt{\beta})^2

\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2 \alpha+\beta+2\sqrt{\alpha\beta}

\bull\sf Put\:values

\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2=\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\sqrt{\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}}

\bull\sf Simplify

\\ \sf{:}\dashrightarrow \underline{\boxed{\bf {\sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\sqrt{\dfrac{-b}{a}}+\sqrt{2}\dfrac{c}{a}}}}

\underline{\bf More\: simplification:-}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{-b}}{\sqrt{a}}+\dfrac{c\sqrt{2}}{a}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{a}\sqrt{-b}+c\sqrt{2}}{a}

\underline{\Large{\bf Simplified\: Answer:-}}

\\ \sf{:}\dashrightarrow\underline{\boxed{\bf{ \sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\dfrac{\sqrt{-ab}+c\sqrt{2}}{a}}}}

5 0
2 years ago
Read 2 more answers
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