(0,8)<br> (-2,0). What is the equation of the linear graph shown?

What is the equation of the line that passes through (6,4) and (4,1)

Murrr4er [49]

Answer:

y = 3/2*x - 5

Step-by-step explanation:

Lets say that P1=(6,4) and P2=(4,1) and that the form of the equation must be y=m*x+b where m is the slope and b the independent variable. Then having two given points we can use the slope formula to find the slope value as:

P1=(x1,y1) and P2=(x2,y2)

slope formula ---> m=(y2-y1)/(x2-x1)

Replacing the given points ---> m=(1-4)/(4-6) = 3/2

then replacing the slope value obtained:

y = 3/2*x + b

Now lets find the value of b. For this we have to replace in the equation a point it can be P1 or P2, i will replace P2:

1 = 3/2*4 + b

1 = 6 + b

1 - 6 = b

-5 = b

therefore the line equation is:

y = 3/2*x - 5

3 0

3 years ago

3x^2-y^3-y^3-z if x=3, y=-2, and z=-5

Serggg [28]

$3(3)^2-(-2)^3-(-2)^3-(-5) = 48$

48 is the answer.

5 0

3 years ago

Read 2 more answers

Hello help pls :3333333 I only need the answer to part B which asks about the mean

statuscvo [17]

Answer:9

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A food company sells salmon to various customers. The mean weight of the salmon is 44 lb with a standard deviation of 3 lbs. The

TiliK225 [7]

Correct question:

A food company sells salmon to various customers. The mean weight of the salmon is 44 lb with a standard deviation of 3 lbs. The company ships them to restaurants in boxes of 9 salmon, to grocery stores in cartons of 16 salmon, and to discount outlet stores in pallets of 64 salmon. To forecast costs, the shipping department needs to estimate the standard deviation of the mean weight of the salmon in each type of shipment. Complete parts (a) and (b) below.

a. Find the standard deviations of the mean weight of the salmon in each type of shipment.

b. The distribution of the salmon weights turns out to be skewed to the high end. Would the distribution of shipping weights be better characterized by a Normal model for the boxes or pallets?

Answer:

Given:

Mean, u = 44

Sd = 3

The company ships in boxes of 9, cartons of 16 and pallets of 64.

a) For the standard deviations of the mean weight of the salmon in each type of shipment, lets use the formula: $\frac{s.d}{\sqrt{u}}$

i) For the standard deviation of the mean weight of salmon in boxes of 9, we have:

$\frac{s.d}{\sqrt{u}}$

$= \frac{3}{\sqrt{9}}$

$= \frac{3}{3} = 1$

The standard deviation = 1

ii) For the standard deviation of the mean weight of salmon in cartons of 16, we have:

$\frac{s.d}{\sqrt{u}}$

$= \frac{3}{\sqrt{16}}$

$= \frac{3}{4} = 0.75$

Standard deviation = 0.75

iii) For the standard deviation of the mean weight of salmon in pellets of 64, we have:

$\frac{s.d}{\sqrt{u}}$

$= \frac{3}{\sqrt{64}}$

$= \frac{3}{8} = 0.375$

Standard deviation = 0.375

b) The distribution of shipping weights would be better characterized by a Normal model for the pallets, because regardless of the underlying distribution, the sampling distribution of the mean approaches the Normal model as the sample increases.

5 0

3 years ago

27 over X =3 and 5y = 35 what is the value of <br> X• Y?

diamong [38]

Answer:

63

Step-by-step explanation:

$\frac{27}{x} = 3$

divide, 27 ÷ 3

you'll get 9, so

x = 9

Next part

5y = 35

divide both sides by 5 to isolate y,

5y ÷ 5 = 35 ÷ 5

=

y = 7

So

x = 9 and y = 7

Then let's add the numbers to our equation ( x × y)

9 × 7

=

63

7 0

3 years ago

(0,8) (-2,0). What is the equation of the linear graph shown?