Question

an electrician has 4.1 meters of wire. How much stripes 7/10m long can he cut? How much wire will he have left over?

Answer 1

From 4.1 meters wire, we can make 5 stripes with 0.6 meters wire being left.

Solution:

Given that, an electrician has 4.1 meters of wire.  

We have to find  

1) Number of stripes 7/10m long can he cut:

Now, we know that, number of stripes he can make $=\frac{\text {available length of wire}}{\text {Length of each stripe}}=\frac{4.1}{\frac{7}{10}}$

$\Rightarrow \frac{4.1}{\frac{7}{10}}=4.1 \times \frac{10}{7}=\frac{41}{7}=5.857$

So, he can make 5 full stripes. We have to neglect fractional value as that is not considered as stripe.

2) Measure of left over wire:

No, we know that, remaining length of wire = total wire length-used length wire  

$\begin{array}{l}{\text { Length of left over wire }=4.1 \text { meters- number stripes used }\times \text {length of each stripe }} \\\\ {\text { Length of left over wire }=4.1-5 \times \frac{7}{10}=4.1-\frac{7}{2}=4.1-3.5=0.6 \text { meters }}\end{array}$

So, 0.6 meters of wire is left.

Answer 2

Answer:

$5$ such strips of $\frac{7}{10}\ m$ can be cut and $\frac{6}{10}\ m$  would be left over.

Step-by-step explanation:

Given is$4.1= \frac{41}{10}\ m$ length of a wire.

We have to cut strips of $\frac{7}{10}\ m$

If we factorize $41 \ by \ 7$

We get $5$ full and and $\frac{6}{7}$

Similarly , if we factorize $\frac{41}{10} \ by \ \frac{7}{10}$

We get full $5 \ strips$ and another $\frac{6}{10} \ m$ would be left.