Edit: 33% is not
, therefore my solution is wrong. The correct answer is 0.33 x 496, which is $163.68
The following is the original solution, which is incorrect.
33% =
. Multiply the bonus of $496 by
to get the solution of
, or 165 and
Therefore the solution is $165.33
Answer:
Here is the process I did:
2(6x+4)-6+2x=3(4x+3)+1
Step 1: Distribute the 2 to the numbers in the parentheses (6x +4) on the left side of the equation
6x(2)+4(2)-6+2x=3(4x+3)+1
12x+8-6+2x=3(4x+3)+1
Step 2: On the left side of the equation combine like terms
x's go with x's (12x and 2x):
(12x + 2x)+8-6=3(4x+3)+1
14x+8-6=3(4x+3)+1
normal numbers go with normal numbers ( 8 and -6):
14x+(8+(-6))=3(4x+3)+1
14x+2=3(4x+3)+1
Step 3: Distribute the 3 to the numbers in the parentheses (4x+3) on the right side of the equation
14x+2=4x(3) +3(3) + 1
14x+2=12x + 9 + 1
Step 4: On the right side of the equation combine like terms
normal numbers go with normal numbers ( 9 and 1):
14x+2=12x + (9 + 1)
14x+2=12x + 10
Step 5: Bring 2 from the left side to the right by subtracting it to both sides
14x+(2-2)=12x + (10-2)
14x = 12x + 8
Step 6: Bring 12x from the right side to the left by subtracting it to both sides
(14x - 12x) = (12x - 12x) + 8
2x = 8
Step 7: Isolate x by dividing 2 to both sides
x = 4
Hope this helped!
$2.00 more.
gathered info from question:
Kai paid $45
Cole paid $24
It is $6 for each pack of pens
So I did 24- 6 (pack of pens) = 18 (what he used for calculators) and then did 18/2 because he bought two calculators. He paid 9 dollars for each calculator
Kai bought two packs of pens = 12 dollars. 45-12=33, how much he used for the calculators. He bought three calculators so I did 33/3=11. He used 11 dollars for each calculator.
11-9=2.
Kai paid $2.00 more than Cole.
Please mark be brainliest :)
Answer:
The area of a sector GHJ is 
Step-by-step explanation:
step 1
we know that
The area of a circle is equal to
we have
substitute
step 2
Remember that the area of a complete circle subtends a central angle of 360 degrees
so
by proportion find the area of a sector by a central angle of 65 degrees
Use 
