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3 years ago

13

Pls help will give brainliest

2 answers:

Neko [114]3 years ago

6 0

Step three is the correct answer

HACTEHA [7]3 years ago

5 0

Answer:

In step three.

I hope this helps and teaches you a lesson.

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Data show that men who are married, and also divorced or widowed men, earn quite a bit more than men the same age who have never

lozanna [386]

Answer:

Work ethic, is a lurking variable, because the work ethic i.e the number of hours worked overtime of single men is often less, while the length of breaks is often more compared to married, divorced or widowed men.

Step-by-step explanation:

In to gain a better understanding of the above answer we need to known that

Men who are married, widowed, or divorced are usually more committed both in their personal and professional lives because of the responsibility of not only taking care of them self but their family, enabling them to succeed in their careers.

4 0

3 years ago

Which is greater 0.21 or 0.12 and why?

tatuchka [14]

0.21 is greater than 0.12 because it in the 20s

6 0

3 years ago

PLZZ I WILL GIVE BRAINLIST PLEASE ANSWER ASAP!!!!

lora16 [44]

Answer:

Option C. -3x^2-13x-5

Step-by-step explanation:

we know that

To find how much greater is the area of room A than the area of room B. subtract the area of room B from the area of room A

so

$(5x^{2}-7x-6)-(8x^{2}+6x-1)\\ \\= (5x^{2}-7x-6)-8x^{2}-6x+1\\ \\=(5x^{2}-8x^{2})+(-7x-6x)+(-6+1)\\ \\=-3x^{2} -13x-5$

8 0

3 years ago

For each pair figures, find the ratio of the area of the first figure to the area of the second. 14mm 7mm

Paraphin [41]

The ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1

<h3>Ratio of the areas of similar figures </h3>

From the question, we are to determine the ratio of the area of the<u> first figure</u> to the area of the <u>second figure</u>

<u />

The two figures are similar

From one of the theorems for similar polygons, we have that

If the scale factor of the sides of <u>two similar polygons</u> is m/n then the ratio of the areas is (m/n)²

Let the base length of the first figure be ,m = 14 mm

and the base length of the second figure be, n = 7 mm

∴ The ratio of their areas will be

$(\frac{14 \ mm}{7 \ mm})^{2}$

$= \frac{196 \ mm^{2} }{49\ mm^{2} }$

$=\frac{4}{1}$

= 4:1

Hence, the ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1

Learn more on Ratio of the areas of similar figures here: brainly.com/question/11920446

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%7B4x%2B1%7D-5%3D0%5C%5C%5C%5C%5C%5C%5C%5C%5Csqrt%7B5x-1%7D%2B3%3Dx%5C%5C" id="TexFormu

adoni [48]

Answer:

what topic is this please

8 0

3 years ago