<span>Triangles exist:
</span>3 acute angles<span>
2 acute angles, 1 right angle
</span><span>2 acute angles, 1 obtuse angle
</span>
Triangles DON'T exist for:
<span>1 acute angle, 1 right angle, 1 obtuse angle
</span><span>1 acute angle, 2 obtuse angles</span>
Answer:
x = 0 and x = 3
Step-by-step explanation:
I will assume that you mean:
4 8
---- + --------- = 4
x x + 2
Here the LCD is x(x + 2).
Multiplying all 3 terms by x(x + 2), we get:
4(x + 2) + 8x = 4(x)(x + 2), or
4x + 8 + 8x = 4x^2 + 8x
Cancelling the 8x terms, we have:
12x = 4x^2, or 3x = x^2, or x^2 - 3x = 0.
Factoring, we get x(x - 3) = 0, which results in x = 0 and x = 3.
that would mean he's 7 right now
