Please help me and I’ll give you brainiest!!!!!

Please help me Write the 2 hundreds each number is between

Ede4ka [16]

53: 800 and 900

54: 700 and 800

55: 500 and 600

56: 2,771,100 and 2,771,200

57: 90,120,000 and 90,120,100

58: 631,900 and 632,000

59: 93,300 and 93,400

60: 200 and 300

61: 900 and 1000

62: 39,576,700 and 39,576,800

63: 24,900 and 25,000

64: 471,100 and 471,200

4 0

3 years ago

An edge can represent ______? A) A stoplight B) A train C) A highway

DiKsa [7]

I would say A) a spotlight cause ussually spotlights are at the end/edge of a road.

8 0

3 years ago

1. Given points ????(3, −5) and ????(19, −1), find the coordinates of point ???? that sit 3/8 of the way along AB ,close to A th

Nastasia [14]

Answer: The required co-ordinates of point C are (9, -3.5).

Step-by-step explanation: We are given the points A(3, -5) and B(19, -1).

We are to find the co-ordinates of point C that sit 3/8 of the way along AB, where the point P is close to A than to B.

According to the given information, we have

$\dfrac{AC}{AB}=\dfrac{3}{8}\\\\\Rightarrow \dfrac{AC}{AC+BC}=\dfrac{3}{8}\\\\\Rightarrow 8AC=3AC+3BC\\\\\Rightarrow 5AC=3BC\\\\\Rightarrow AC:BC=3:5.$

So, point C divides the line segment AB in the ratio 3 : 5.

We know that

if a point Q divides a line segment joining the points S(a,b) and T(c,d), in the ratio m : n, then the co-ordinates of Q are

$\left(\dfrac{mc+na}{m+n},\dfrac{md+nb}{m+n}\right).$

Therefore, the co-ordinates of point C are

$\left(\dfrac{3\times19+5\times3}{3+5},\dfrac{3\times(-1)+5\times(-5)}{3+5}\right)\\\\\\=\left(\dfrac{57+15}{8},\dfrac{-3-25}{8}\right)\\\\=(9,-3.5).$

Thus, the required co-ordinates of point C are (9, -3.5).

3 0

4 years ago

*PLEASE HELP*

ra1l [238]

Answer:

(3x5)+(5x2)=25

Step-by-step explanation:

3x5=15 plus 5x2=10 15+10=25

7 0

3 years ago

the first four terms in an arithmetic sequence are $x y$, $x - y$, $xy$, and $x/y$, in that order. what is the fifth term?

olga2289 [7]

When the first four terms in an arithmetic sequence are x+y, x-y, xy and x÷y, then the fifth term will be $\frac{123}{40}$

A sequence of numbers in which every term (except the first term) is obtained by adding a constant number to the previous term is called an arithmetic sequence

In given arithmetic sequence

The first term = x+y

The second term = x-y

Then, the common difference= (x-y)-(x+y)

x-y-x-y= -2y

The third term = x-y+(-2y)

x-y-2y= x-3y

In question third term is given as xy

So both are equal

x-3y=xy

-3y=xy-x

-3y=x(y-1)

x= $\frac{-3y}{y-1}$

Similarly fourth term will be

x-3y-2y=x-5y

$x-5y=\frac{x}{y}$

substitute the value of x in the equation

$\frac{-3y}{y-1}-5y=\frac{\frac{-3y}{y-1} }{y} \\\frac{-3y}{y-1} -5y=\frac{-3}{y-1}\\ -3y-5y(y-1)=-3\\-3y-5y^{2}+5y=-3\\ -5y^{2} +2y+3=0\\5y^{2} -2y-3=0$