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3 years ago

Which equation should you solve to find x?

Mathematics

1 answer:

Vikentia [17]3 years ago

7 0

D
Cosine= adjacent / hypotenuse

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Find the arc length of the given curve between the specified points.

yuradex [85]

Answer:

4.25

Step-by-step explanation:

Given:

$f(x) = \frac{x^3}{12} + \frac{1}{x} \\\\Arc Length = \int\limits^a_b {\sqrt{1 + (f'(x))^2} } \, dx \\f '(x) = \frac{x^2}{6} - \frac{1}{x^2}\\\\f'(x)^2 = (\frac{x^2}{6} - \frac{1}{x^2})^2 = \frac{x^4}{36} + \frac{1}{x^4} - \frac{1}{3}\\\\1 + f'(x)^2 = \frac{x^4}{36} + \frac{1}{x^4} + \frac{2}{3}\\\\\= \frac{x^8 + 36 + 12x^4}{36x^4}\\\\= \frac{(x^4 + 6)^2}{36x^4}\\\\=\sqrt{1 + f'(x)^2} = \sqrt{ \frac{(x^4 + 6)^2}{36x^4}}\\\\= \frac{x^2}{6} + \frac{1}{x^2} \\\\$

$ArcLength = \int\limits^4_1 {\frac{x^2}{6} + \frac{1}{x^2} } \, dx \\= (\frac{x^3}{18} - \frac{1}{x})\limits^4_1\\\\= (\frac{64}{18} - \frac{1}{4}) - (\frac{1}{18} - 1)\\\\= \frac{17}{4}= 4.25$

8 0

3 years ago

ANSWER THESE ASAP Carla got a ride from her mom to school on 13 of 20 school days in November. Which is NOT equivalent to the fr

Artyom0805 [142]

question 1: 35%

question 2: 0.23

question 3: 9/20

question 4: 1,360 mL

question 5: 1,994 yds

7 0

3 years ago

Read 2 more answers

ASAP! GIVING BRAINLIEST! Please read the question THEN answer CORRECTLY! NO guessing. Show your work OR give an explaination.

love history [14]

Answer:

$\boxed{D. 3 {x}^{2} - x - 6}$

Given:

$f(x) = 3{x}^{2} - 4 \\ \\ g(x) = x + 2$

To Find:

$(f - g)(x) = f(x) - g(x)$

Step-by-step explanation:

$= > f(x) - g(x) = (3{x}^{2} - 4) - (x + 2) \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3{x}^{2} - 4 -(x) - (2)\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =3{x}^{2} - 4 - x - 2\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =3 {x}^{2} - x - 6$

8 0

3 years ago

Consider the shape of this data.

djyliett [7]

B I assume, not 100% sure

4 0

3 years ago

Find two positive numbers such that the sum of the first and twice the second is 56 and whose product is a maximum

Svetlanka [38]

Let
x-------> the first number
y-------> the second number
P-----> product

we know that
x+2y=56----------> 2y=56-x-----> y=28-0.5x------> equation 1
P=x*y----> equation 2

substitute equation 1 in equation 2
P=x*[28-0.5x]-----> P=28x-0.5x²

using a graph tool
see the attached figure
the vertex is the point (28,392)
that means
for x=28
the product is 392 (maximum)
find the value of y
y=28-0.5x----> y=28-0.5*28----> y=14

the answer is
the numbers are 28 and 14

5 0

4 years ago

Which equation should you solve to find x? ​

Which equation should you solve to find x?