Translate the following statement into an inequality. Use x as the variable.
1 answer:
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In order to be differentiable everywhere, must first be continuous everywhere, which means the limits from either side as
must be the same and equal to
. By definition,
, and
so we need to have .
For to be differentiable at
, the derivative needs to be continuous at
, i.e.
We then need to have
Then
Answer:
And solving we have:
And we can write the expression like this:
The vertex for this case would be:
And the minimum for the function would be 3 and there is no maximum value for the function
Step-by-step explanation:
For this case we have the following equation given:
We can complete the square like this:
And solving we have:
And we can write the expression like this:
The vertex for this case would be:
And the minimum for the function would be 3 and there is no maximum value for the function