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Oduvanchick [21]
3 years ago
12

What is the distance between A(5, 4) and B(2, -3)?

Mathematics
2 answers:
netineya [11]3 years ago
8 0

Answer:

(3,1)

Step-by-step explanation:

i believe this is correct

valentina_108 [34]3 years ago
5 0

Answer:

7.6

Step-by-step explanation:

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3-7=<br> 4-6=<br> 3+-6=<br> 4--1=<br> -5+-5=<br> -3+5=<br> -4-6=
kipiarov [429]

Answer:

Answers are below

Step-by-step explanation:

3 - 7 = -4

4 - 6 = -2

3 + -6 = -3

4 - - 1 = 5

-5 + -5 = -10

-3 + 5 = 2

-4 -6 = -10

Hope this helps!!

4 0
3 years ago
-2a<br> 0b<br> -2<br> × -5b<br> 4<br> × -b
lakkis [162]

Answer:

Step-by-step explanation:

Army DA administrative publications and forms by the Army Publishing Directorate APD. The latest technologies high quality electronic pubs and forms view ...

8 0
3 years ago
Help need the answer quick
Shalnov [3]

Answer:

1A

2H

3D

4C

5G

6E hope this helps

6 0
3 years ago
A car rental costs $50 for the first day. Additional days cost $35 per day, unless the car is rented for 7 days or more, in whic
son4ous [18]

Answer:

\$50+\$31.5x

Step-by-step explanation:

Let

x------> the number of days

y----> the cost of renting a car

we know that

For x

y=\$50+\$35x

For x\geq 7\ days

The rate is equal to

0.90*\$35=\$31.5

so

y=\$50+\$31.5x

In this problem. the car has been rented for more than a week

therefore

x> 7\ days

The cost of renting a car is equal to

y=\$50+\$31.5x

6 0
3 years ago
in a standard casino dice game the roller wins on the first roll if he rolls a sum of 7 or 11. what is the probability of winnin
Alborosie

<u>Answer-</u>

<em>The probability of winning on the first roll is </em><em>0.22</em>

<u>Solution-</u>

As in the game of casino, two dice are rolled simultaneously.

So the sample space would be,

|S|=6^2=36

Let E be the event such that the sum of two numbers are 7, so

E = {(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)}

|E|=56

\therefore P(E)=\dfrac{|E|}{|S|}=\dfrac{6}{36}

Let F be the event such that the sum of two numbers are 11, so

F = {(6,5), (5,6)}

|F|=2

\therefore P(F)=\dfrac{|F|}{|S|}=\dfrac{2}{36}

Now,

P(\text{sum is 7 or 11)}=P(E\ \cup\ F)=P(E)+P(F)=\dfrac{6}{36}+\dfrac{2}{36}=\dfrac{8}{36}=\dfrac{2}{9}=0.22

8 0
4 years ago
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