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2 years ago

What equation corresponds with the situation?

Mathematics

1 answer:

madreJ [45]2 years ago

8 0

Answer:

Story 1

Step-by-step explanation:

For story 1:

Lin gave 12 flyers to 3 people. She took the remaining flyers (90 - (12*3)) and divided then into groups of 3 to give to the volunteers. That would be 3(12) + 3(y) = 90 which is also 3(12+y) = 90.

For story 2:

The equation would be "3(y) + 12 = 90" and not "3(12+y) = 90"

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Step-by-step explanation:

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3 years ago

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3 years ago

Factor out the GCF of 16x3−4x2+24x

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3 years ago

The reported average cost per workbook at a large college is $27.50. A professor claims that the actual average cost per workboo

nadezda [96]

Answer:

We conclude that the actual average cost per workbook is higher than $27.50.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = $27.50

Sample mean, $\bar{x}$ = $28.90

Sample size, n = 44

Alpha, α = 0.05

Population standard deviation, σ = $5.00

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 27.50\text{ dollars}\\H_A: \mu > 27.50\text{ dollars}$

We use one-tailed z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{28.90 - 27.50}{\frac{5.00}{\sqrt{44}} } = 1.8573$

Now, $z_{critical} \text{ at 0.05 level of significance } = 1.64$

Since,

$z_{stat} > z_{critical}$

We reject the null hypothesis and accept the alternate hypothesis.

Thus, we conclude that the actual average cost per workbook is higher than $27.50.

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4 years ago

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4 years ago