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poizon [28]
3 years ago
6

Dylan is evaluating the expression 13 + 19 + 7 + 10. At one step in his work, Dylan rewrites the equation as 13 + 7 + 19 + 10. W

hich property of addition must Dylan have used when he evaluated the expression?
associative property
commutative property
distributive property
identity property
Mathematics
2 answers:
musickatia [10]3 years ago
7 0

Answer:

1

Step-by-step explanation:

i am not sure but that is what i got.

azamat3 years ago
6 0

Answer:

b). Commutative property

Step-by-step explanation:

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Calculate m∠ADC. Round to the nearest thousandth.
stira [4]

Answer:  54.508^{\circ}

Step-by-step explanation:

Let the angle ADC = x degree

Since, By the given diagram, In triangle BDC,

\frac{BC}{DC} = tan27^{\circ}

⇒ \frac{BC}{19.6} = tan27^{\circ}

⇒ BC = 19.6\times tan 27^{\circ}

⇒  BC = 9.98669881009

Now, In triangle ADC,

tan x =\frac{AC}{DC}

⇒  tan x =\frac{AB+BC}{DC}

⇒  tan x =\frac{17.5+9.98669881009}{19.6}

⇒  tan x =\frac{27.4866988101}{19.6}

⇒  tan x =1.40238259235

⇒  x = 54.508389368\text{ degree} \approx 54.508^{\circ}

4 0
3 years ago
How many different sandwiches can you make using one spread, one type of bread, and one type of meat?
kykrilka [37]
You can make 9 sandwiches
6 0
4 years ago
What is the equation of the horizontal line graphed below?
BartSMP [9]
The answer is y = -4

because the line is on the y-axis on -4. If it was x = -4 then the line would be vertical on -4 on the x-axis

4 0
4 years ago
Read 2 more answers
A manufacturer makes ball bearings out of motel steel. it takes 5.24 cubic centimeters of molten steel to make ball bearings tha
katrin2010 [14]

Using volume of ball bearings, a manufacturer makes 10 ball bearings from 5.2 cm³ of molten steel to make ball bearings that each have a diameter of 1 centimeter.

According to the question,

It takes 5.24 cubic centimeters of molten steel to make ball bearings that each have a diameter of 1 centimeter.

Radius = 1/2 = 0.5 cm

volume V of one ball bearing is: V=(4/3)*π*r³

= 4/3 * π * (0.5)³

=0.524 cm³

In order to find number of ball bearings out of molten steel only if we divide the volume of steel by the volume of the ball bearing

5.24/0.524=10.

Hence, using volume of ball bearings, a manufacturer makes 10 ball bearings from 5.2 cm³ of molten steel to make ball bearings that each have a diameter of 1 centimeter.

Learn more about volume here

brainly.com/question/23270880

#SPJ4

4 0
2 years ago
Calculus piecewise function. ​
Kipish [7]

Part A

The notation \lim_{x \to 2^{+}}f(x) means that we're approaching x = 2 from the right hand side (aka positive side). This is known as a right hand limit.

So we could start at say x = 2.5 and get closer to 2 by getting to x = 2.4 then to x = 2.3 then 2.2, 2.1, 2.01, 2.001, etc

We don't actually arrive at x = 2 itself. We simply move closer and closer.

Since we're on the positive or right hand side of 2, this means we go with the rule involving x > 2

Therefore f(x) = (x/2) + 1

Plug in x = 2 to find that...

f(x) = (x/2) + 1

f(2) = (2/2) + 1

f(2) = 2

This shows \lim_{x \to 2^{+}}f(x) = 2

Then for the left hand limit \lim_{x \to 2^{-}}f(x), we'll involve x < 2 and we go for the first piece. So,

f(x) = 3-x

f(2) = 3-2

f(2) = 1

Therefore, \lim_{x \to 2^{-}}f(x) = 1

===============================================================

Part B

Because \lim_{x \to 2^{+}}f(x) \ne \lim_{x \to 2^{-}}f(x) this means that the limit \lim_{x \to 2}f(x) does not exist.

If you are a visual learner, check out the graph below of the piecewise function. Notice the gap or disconnect at x = 2. This can be thought of as two roads that are disconnected. There's no way for a car to go from one road to the other. Because of this disconnect, the limit doesn't exist at x = 2.

===============================================================

Part C

You'll follow the same type of steps shown in part A.

However, keep in mind that x = 4 is above x = 2, so we'll deal with x > 2 only.

So you'd only involve the second piece f(x) = (x/2) + 1

You should find that f(4) = 3, and that both left and right hand limits equal this value. The left and right hand limits approach the same y value. The limit does exist here. There are no gaps to worry about when x = 4.

===============================================================

Part D

As mentioned earlier, since \lim_{x \to 4^{+}}f(x) = \lim_{x \to 4^{-}}f(x) = 3, this means the limit \lim_{x \to 4}f(x) does exist and it's equal to 3.

As x gets closer and closer to 4, the y values are approaching 3. This applies to both directions.

4 0
2 years ago
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