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Tanya [424]
3 years ago
8

A large tank of fish from a hatchery is being delivered to a lake. The hatchery claims that the mean length of fish in the tank

is 15 inches, and the standard deviation is 6 inches. A random sample of 46 fish is taken from the tank. Let x be the mean sample length of these fish. What is the probability that x is within 0.5 inch of the claimed population mean?
Mathematics
1 answer:
djverab [1.8K]3 years ago
8 0

Answer:

0.4246

Step-by-step explanation:

Given data:

mean (<em> u</em> ) = 15 inches

std ( б )= 6 inches

sample size( n ) = 46

<em>u</em>x = mean sample length

Determine the probability that x within 0.5 inch of the claimed population mean

<em>u</em>x = <em>u = </em>15

бx = б/ √ 46 =  6 /√ 46 = 6 / 6.78 = 0.88

Hence the   P( 14.5 < x < 15.5 )

= P ( [14.5 - 15 / 0.88 ] < z < (15.5 - 15) / 0.88) )

= P ( -0.5682 < z <  0.5682 )

= P ( z < 0.5682 ) - P ( z < -0.5682 )

= 0.7123 - 0.2877  ( from Z table )

= 0.4246

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         = \frac{135-125}{30-10}\\\\= \frac{10}{20}\\\\= \frac{1}{2}\\= 0.5

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Answer:

2. b : l

3. 20cm

4. 49 cm^{2}

5. (2\pi+1):2\pi

Step-by-step explanation:

<u>Solution 2:</u>

Let cylinder is rolled along 'l':

Height of cylinder , h = length of rectangle = l

Perimeter of base = b

Let 'r' be the radius of cylinder's base:

2\pi r = b\\\Rightarrow r = \dfrac{b}{2\pi}

Volume of a cylinder is given as:

V = \pi r^{2} h

Putting the values:

V_1 = \pi (\dfrac{b}{2\pi})^2 l\\\Rightarrow V_1 =  (\dfrac{b^2}{4\pi}) l

Let cylinder is rolled along 'b':

Height of cylinder , h = length of rectangle = b

Perimeter of base = l

Let 'r' be the radius of cylinder's base:

2\pi r = l\\\Rightarrow r = \dfrac{l}{2\pi}

Volume of a cylinder is given as:

V = \pi r^{2} h

Putting the values:

V_2 = \pi (\dfrac{l}{2\pi})^2 b\\\Rightarrow V_2 =  (\dfrac{l^2}{4\pi}) b

Taking ratio:

V_1:V_2 = \dfrac{(\dfrac{b^2}{4\pi}) l}{(\dfrac{l^2}{4\pi}) b} = b:l

Solution 3:

Rectangle is rolled along its length to make a cylinder, so height will be equal to its length.

\therefore height of cylinder = 20 cm

Solution 4:

Side of square = 7 cm

Height of cylinder =Side of square = 7 cm

7 cm will be the circumference of the circle.

i.e. 2\pi r = 7 cm

Curved surface area of a cylinder:

CSA = 2\pi rh

Putting the above values:

CSA = 7 \times 7 = 49 cm^{2}

Solution 5:

As calculated in above step:

CSA = 2\pi rh = 7 \times 7 = 49 cm^{2}

Total surface area = 2\pi r^{2} + 2\pi r h

Calculating value of r:

2\pi r = 7 cm

\Rightarrow 2  \pi r = 7\\\Rightarrow r = \dfrac{7}{2\pi}

Total surface area =

2\pi (\dfrac{7}{2\pi})^{2} + 49\\\Rightarrow \dfrac{49}{2\pi}+49\\\Rightarrow 49(\dfrac{1}{2\pi}+1) cm^2

Ratio of TSA: CSA is

49(\dfrac{1}{2\pi}+1) cm^2 : 49 cm^2\\\Rightarrow (\dfrac{1}{2\pi}+1):1\\\Rightarrow (2\pi+1): 2\pi

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