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Temka [501]
2 years ago
14

If m∠BDC=(8x+12)° and m∠FDB=(12x−32)°, find m∠FDE.

Mathematics
1 answer:
tensa zangetsu [6.8K]2 years ago
7 0
12x-8x hughggfhjgjggg
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Evaluate 6x + 11 when x = 7
nlexa [21]

Answer:

53

Step-by-step explanation:

To evaluate 6x + 11, we must substitute the value of x.

Since we know that x = 7, it is easier to evaluate the expression;

6x + 11

6(7) + 11

Since 6 is outside the parenthesis, we must multiply everything inside the parenthesis by 6;

6(7) + 11

42 + 11

When you add the two numbers you get:

53

4 0
3 years ago
The sales tax on a used car is​ $174​, and the sales tax rate is 5​%. Find the purchase price ​(the price before taxes are​ adde
rosijanka [135]

Answer:

Step-by-step explanation:

Let x be the purchase price

5% of x = $ 174

\frac{5}{100}*x=174\\\\x=174*\frac{100}{5}\\\\x=174*20\\

Purchase price = $ 3480

8 0
3 years ago
Find the area of the trapezoid. A. 675 ft2 B. 337.5 ft2 C. 187.5 ft2 D. 150 ft2
Grace [21]
I think ur answer will be b
5 0
3 years ago
Read 2 more answers
Suppose that you can only use the set of small letters characters (a-z) and odd numbers (1, 3, 5, 7, 9) to set a password. What
Flauer [41]

Answer:

31^8

Step-by-step explanation:

To create a password, you need to select 8 characters (not necessarily different) from the set {1,3,5,7,9,a,b,c,...,z}. Now, this set has 31 elements: the 26 lowercase letters from the alphabet and the 5 odd numbers (1,3,5,7,9).

Now, there are 31 ways to choose the first character, it can be any element from our set. The second character can also be chosen in 31 ways, because there are not restrictions (repetitions, specific characters, etc). Similarly, the third, fourth, fifth, sixth, seventh and eighth characters have 31 possibilities each one.

The number of passwords is the number of ways of selecting the 8 characters, then by the multiplication principle the number of passwords is 31×31×31×31×31×31×31×31=31^8.

6 0
4 years ago
6. What is the distance between -3 and 2 on the number line?
icang [17]

Answer:

5 jumps to the right

<h2><u><em>hope it helps :D</em></u></h2>

7 0
3 years ago
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