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DaniilM [7]
3 years ago
13

What function is the inverse ?

Mathematics
1 answer:
Elodia [21]3 years ago
7 0
To solve for the inverse function. All you would have to do is switch the X and y variables in the original equation and solve for the new y variable.

Y = 2x + 3
X = 2y + 3
X - 3 = 2y
Y = (X - 3)/2

Or Y = 1/2x - 3/2.
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Answer:

252

Step-by-step explanation:

t50 = t1 + (n - 1)(d)

= 7 + (50 - 1) (5)

= 7 + (49)(5)

= 7 + 245

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6 0
3 years ago
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Prove that (Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A
iVinArrow [24]

Answer:

The answer is below

Step-by-step explanation:

We need to prove that:

(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.

Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.

Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A

\frac{\sqrt{secA-1} }{\sqrt{secA+1} } +\frac{\sqrt{secA+1} }{\sqrt{secA-1} } =\frac{(\sqrt{secA-1)}(\sqrt{secA-1})+(\sqrt{secA+1)}(\sqrt{secA+1}) }{(\sqrt{secA+1})(\sqrt{secA-1}) } \\\\=\frac{secA-1+(secA+1)}{\sqrt{sec^2A-secA+secA-1} } \\\\=\frac{2secA}{\sqrt{sec^2A-1} } \\\\=\frac{2secA}{\sqrt{tan^2A} } \\\\=\frac{2secA}{tanA} \\\\=\frac{2*\frac{1}{cosA} }{\frac{sinA}{cosA} }\\\\= 2*\frac{1}{cosA}*\frac{cosA}{sinA}\\\\=2*\frac{1}{sinAA}\\\\=2cosecA

7 0
3 years ago
Equations that equal 12
crimeas [40]
I hope this helps you


12=3.4=3.2^2
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Serga [27]

Answer:

D

Step-by-step explanation:

8 0
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13. How are squares and triangles the same? How are they different?​
nignag [31]

Answer:

Squares and triangles are both polygons and right triangles and squares both have at least one right angle. They are different because squares have 4 sides and triangles have 3. Also, triangle have a total of 180 degrees while squares have a total of 360 degrees.

Hope this helped you! I would appreciate a Brainliest if this helped! Have a good day!

4 0
2 years ago
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