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Nikitich [7]
3 years ago
9

Add 3 5/6 + 2 5/9 simplify the answer and multiply as a mixed number

Mathematics
1 answer:
raketka [301]3 years ago
5 0

Answer:

6.38

Step-by-step explanation:

3 5/6 + 2 5/9

= 115/18

= 6.38

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A circular railroad-crossing sign has a diameter of 30 inches.
Angelina_Jolie [31]

Diameter = 30

30/2 = 15 15 is the radius

To find area:

3.14 x 15 x 15 = 706.5

706.5 is the answer

6 0
2 years ago
The moon takes 28 days to orbit around the earth going at a distance of 2,413,000. How many kilometers does it take for the moon
Mazyrski [523]

Answer:

As per the statement;

The moon takes 28 days to orbit around the earth going at a distance of 2,413,000 km

From the above information,

The ratio between Distance and Days is; \frac{2413000}{28}

then,

the distance it takes for the moon to travel one day of its orbit around the earth we have;

\frac{2413000}{28} \times 1 = \frac{2413000}{28}=86178.57 km.

Therefore, the distance in kilometer does the moon cover in 1 day is 86178.57 km


8 0
3 years ago
Read 2 more answers
Convert 12 and a half of 30
tamaranim1 [39]

Answer:

375

Step-by-step explanation:

12½[30] → 25⁄2[30]

Multiply 25 by 30 [750] then divide by 2 to get 375.

I am joyous to assist you anytime.

7 0
4 years ago
A laundry mat can clean five shirts in 20 minutes. What is the rate of shirts per hour?
Anna11 [10]

Answer:

15 shirts in one hour

Step-by-step explanation:

there are 60 minutes in an hour, 20 times 3 is 60, 5 times 3 is 15

5 0
3 years ago
Find the area of the right triangle △DEF with the points D (0, 0), E (1, 1), and F.
Tems11 [23]

Answer:

The area of the triangle is  \sqrt{3}

Step-by-step explanation:

Given:

Coordinates D (0, 0), E (1, 1)

Angle  ∠DEF = 60°

△DEF is a Right triangle

To Find:

The area of the triangle

Solution:

The area of the triangle is  = \frac{1}{2}(base \times height)

Here the base is Distance between D and E

calculation the distance using the distance formula, we get

DE  = \sqrt{(0-1)^2 + (0-1)^2}

DE =\sqrt{(-1) ^2 + (-1)^2

DE = \sqrt{1+1}

DE = \sqrt{2}

Base = \sqrt{2}

Height is DF

DF =tan(60^{\circ}) \times DE

DF = \sqrt{3} \times DE

DF = \sqrt{3} \times\sqrt{2}

Now, the area of the triangle is

= \frac{1}{2}({\sqrt{2})(\sqrt{3} \times \sqrt{2})

=\frac{1}{2}({\sqrt{2})(\sqrt{3} \sqrt{2})

=\frac{1}{2}(2\sqrt{3} )

=\sqrt{3}

6 0
3 years ago
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