Chemical reaction: SO₄²⁻ + Ba²⁺ → BaSO₄.
m(sample) = 1,543 g.
m(BaSO₄) = 0,2243 g.
n(BaSO₄) = m(BaSO₄) ÷ M(BaSO₄).
n(BaSO₄) = 0,2243 g ÷ 233,4 g/mol.
n(BaSO₄) = 0,00096 mol.
n(BaSO₄) = n(SO₄²⁻).
ω(SO₄²⁻) = m(SO₄²⁻) ÷ m(sample).
ω(SO₄²⁻) = 0,00096 mol · 96 g/mol ÷ 1,543 g.
ω(SO₄²⁻) = 0,059 = 5,9%.
Answer:
b.fission, because the reaction absorbed energy
Explanation:
It would be:
2H2 + O2 -> 2H2O
Answer: Heat of reaction ∆H = -13.43kJ
Explanation:
The number of moles of NaOH = the number of moles of HCL = N
N = concentration × volume= CV = 0.5M × 500mL/1000ml/L
N= 0.5 × 0.5= 0.25mol
Since the Molar enthalpy is given by Hm = -53.72kJ/mol
Heat of reaction ∆H = N×Hm
∆H= 0.25mol × -53.72kJ/mol = -13.43kJ
Heat of reaction ∆H = -13.43kJ
