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Sever21 [200]
3 years ago
15

For a sample of stomach acid that is 2.02×10−2 M in HCl, how many moles of HCl are in 14.6 mL of the stomach acid?

Chemistry
1 answer:
GaryK [48]3 years ago
8 0

Answer:

0.0002949 moles

Explanation:

Concentration = 2.02×10−2 M

Volume = 14.6 mL = 0.0146 L (Upon converting to litres)

Number of moles = ?

These variables are related by the fllowing equation;

Concentration = Number of moles / Volume

Number of moles = Concentration * Volume

Number of moles = 2.02×10−2 * 0.0146 = 0.0002949 moles

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3 years ago
If a 1.45 M solution has 2.43 g HCl dissolved, what is the volume of solution? (Change g Hl into mol using molar mass)
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3 years ago
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laila [671]

Answer:

  • <u>1. Equation: 2x  + 3 = 9x - 11</u>

<u></u>

  • <u>2. Each row has 2 chairs</u>

Explanation:

The variable x represents the number of chairs in each row.

<u />

<u>1. She can form 2 rows of a given length with 3 chairs left over.</u>

Thus, she has:

number of rows  number of chairs in      chairs             number of chairs

                             each row                       left over         she has

     2                        x                                    3                      2x + 3

<u>2.  She can form 9 rows of the same length if she gets 11 more chairs.</u>

That means that she is short in 11 chairs to have 9x chairs, or that she has 11 less chairs than 9x chairs. Then she has:

  • 9x - 11

<u>3. Equation:</u>

Then, number of chairs she has is 2x + 3 and, also, 9x - 11, which allows to set the equation:

  • 2x + 3 = 9x  -11

<u>4. Solve the equation:</u>

  • 9x - 2x = 3 + 11
  • 7x = 14
  • x = 2

Therefore, each row has 2 chairs, and she has 2x + 3 = 4 + 3 = 7 chairs.

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3 years ago
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