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2 years ago

For a sample of stomach acid that is 2.02×10−2 M in HCl, how many moles of HCl are in 14.6 mL of the stomach acid?

Chemistry

1 answer:

GaryK [48]2 years ago

8 0

Answer:

0.0002949 moles

Explanation:

Concentration = 2.02×10−2 M

Volume = 14.6 mL = 0.0146 L (Upon converting to litres)

Number of moles = ?

These variables are related by the fllowing equation;

Concentration = Number of moles / Volume

Number of moles = Concentration * Volume

Number of moles = 2.02×10−2 * 0.0146 = 0.0002949 moles

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Given parameters:

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Unknown:

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After 25 days, it remains radon 5.9x10^5 atoms.

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t1/2(Ra) = 3.8 days; the half-life of the radon is 3.8 days

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