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Answer:
(15,-14)
Step-by-step explanation:
Given that,
The midpoint of FG is (6-4) and the corrdinates of F are (-3,6).
Let (x,y) be the coordinates of point G. Using mid point formula,

So, the coordinates of G are (15,-14).
It would be 100. Hope it helps!
Answer:
Step-by-step explanation:
Let u = x.lnx, , w= x and t = lnx; w' =1 ; t' = 1/x
f(x) = e^(x.lnx) ; f(u) = e^(u); f'(u) = u'.e^(u)
let' find the derivative u' of u
u = w.t
u'= w't + t'w; u' = lnx + x/x = lnx+1
u' = x+1 and f'(u) = ln(x+1).e^(xlnx)
finally the derivative of f(x) =ln(x+1).e^(x.lnx) + 2x