The equation ofa line that passes throug (x1,y1) and has s slope of m is
y-y1=m(x-x1)
given
point is (-1,-3) and slope=4
y-(-3)=4(x-(-1)) or
y+3=4(x+1)
B is the answer
Answer: q=16
Step-by-step explanation:
if we suppose q=16
(q+4)/2=10
X + 9 = 2x - 3
<u>-x -x </u>
9 = x - 3
<u> +3 +3</u>
12 = x
Answer:
x = 2
Step-by-step explanation:
logx + log(2x - 1) = log 6
Apply log rules,
x(2x - 1) = 6
2x^2 - 1x = 6
x = 2 (true) or x = -3/2 (False)
