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2 years ago

The value -2 is a lower bound for the zeros of the function shown below.

Mathematics

1 answer:

Sedaia [141]2 years ago

8 0

I think it is true please let me know if it is right

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Someone help, please and thank you

taurus [48]

Answer:

6√2

Step-by-step explanation:

Given,

θ = 45

Opposite side = 6

To find : - Hypotenuse

Formula : -

sin θ = Opposite side / Hypotenuse

[ The value of sin 45 = 1 / √2 ]

sin 45 = 6 / Hypotenuse

1 / √2 = 6 / Hypotenuse

Cross multiply,

Hypotenuse = 6√2

8 0

2 years ago

Read 2 more answers

Describe a real world situation for the equation +4+(-4=0

Likurg_2 [28]

You could use the equation
+4+(-4)=0 if:

-you earn $4 and spend it

-buying 4 candy bars then eating them

-earning 4 points then losing them

6 0

3 years ago

1. Use the image of the circle to identify the length of the radius, diameter, and circumference. Leave all answers in terms of

Grace [21]

Answer:

Radius = r = 7.5

Diameter = d = 15

Circumference = C = 15π

Step-by-step explanation:

We are given the image of a circle with a straight line passing through the center of the circle and touching its edges. Such a line is known as the diameter of the circle. From the image we can see the length of the diameter of the circle is d = 15 units.

Radius is define as half of the diameter. Since the diameter is 15 units, the radius of the given circle will be half of 15 which is r = 7.5 units.

Circumference of the circle = C = 2πr

Using the value of radius(r), we can write the circumference as:

C = 2π(7.5) = 15π

5 0

3 years ago

What fraction is 18 kg of 64kg?

SSSSS [86.1K]

Answer:

18 Kg of 64 Kg represents 9/32 parts

Step-by-step explanation:

We first represent the 18lg of the 64kg as a fraction that can still be reduced:

$\rm Fraction: \: \dfrac{18kg}{64kg}$

We see that the fraction can be reduced to its half, because both the numerator and the denominator can be simplified by 2.

$\rm \dfrac{18kg :2}{64kg :2} = \dfrac{9}{32}$

By so:

<h3>18 Kg of 64 Kg represents 9/32 parts</h3>

7 0

2 years ago

In the two upcoming basketball games, the probability that utc will defeat marshall is 0.63, and the probability that utc will d

boyakko [2]

Let $M$ denote the event that UTC beats Marshall, so that $\mathbb P(M)=0.63$ , and let $F$ denote the event that UTC beats Furman, so that $\mathbb P(F)=0.55$ . We're told that the UTC has a $\mathbb P(M\cap F)=0.3465$ probability of beating both Marshall and Furman.

So, by the definition of conditional probability, the probability of UTC beating Furman after having beaten Marshall is

$\mathbb P(F\mid M)=\dfrac{\mathbb P(F\cap M)}{\mathbb P(M)}=\dfrac{0.3465}{0.63}=0.55$

5 0

3 years ago