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alexdok [17]
3 years ago
14

The annual rainfall in a certain region is approximately normally distributed with mean 41.8 inches and standard deviation 5.8 i

nches. Round answers to the nearest tenth of a percent.
a) What percentage of years will have an annual rainfall of less than 44 inches?
__%
b) What percentage of years will have an annual rainfall of more than 39 inches?
__%
c) What percentage of years will have an annual rainfall of between 37 inches and 42 inches?
__%
Mathematics
1 answer:
kicyunya [14]3 years ago
8 0
I believe the answer would be B
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Answer:

  about $171,400

Step-by-step explanation:

William's total monthly debt is ...

  $1012.84 +579.13 +250 +300 = 2141.97

On an annual basis, this is ...

  12 × $2141.97 = $25,703.64

This will be 15% of (25703.64/0.15) = $171,357.60.

William's new annual salary should be about $171,400 to keep his debt ratio at the recommended 15%.

_____

<em>Additional comment</em>

A debt ratio of 15% is a pretty aggressive target. Most mortgage lenders like to see the "front end" ratio (housing expense) less than 28%, and the "back end" ratio (all debt) less than 36%.

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\text{The domain:}\\2x+1\geq0\to 2x\geq-1\to x\geq-0.5\\\\D:x\geq0.5\to x\in\left\ \textless \ 0.5;\ \infty\right)\\\\\sqrt{2x+1}=3\ \ \ \ |\text{square both sides} \\2x+1=3^2\\2x+1=9\ \ \ |-1\\2x=8\ \ \ \ |:2\\x=4\in D\\\\\text{Answer: x =0, solution is not extraneous}.
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storchak [24]

<em>p</em> ² + 6 is even if <em>p</em> ² is even (the sum of two even numbers is even), and this happens only if <em>p</em> itself is even, i.e. if <em>p</em> = 2 since 2 is the only even prime.

All other primes <em>p</em> are odd, so <em>p</em> ² would be odd, and adding 6 would not change that (odd + even = odd).

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Solving for Y:

1) Subtract -2x from both sides: -3y=15-2x

2) Divide by -3 on both sides: y=-5+(2/3)x

Final Answer: y = (2/3)x-5
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