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valentina_108 [34]
3 years ago
15

What write a fraction that is a multiple of 4/5

Mathematics
2 answers:
lukranit [14]3 years ago
7 0
= 8/10 = 12/15 = 15/20 = 20/25 hope it help and make me the brainlyiest answer please.
ahrayia [7]3 years ago
5 0
Its 8/10 or 12/15 because 4 times 2 is 8 and 5 times 2 is ten
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The girl scouts are planning to sell chocolate cookies at $10.50 and lollipops at $2.50 each. They were able to collect $350 in
12345 [234]

Answer: 389

Step-by-step explanation: well if there is lollipops for $2.50 each and they sold thrice as many lollipops then they have sold 7.5 of the lollipops and if you sell thrice of the cookies then that will be 31.5 and if you add 7.5 and 31.5 that will be 39 so the real answer is 389.

5 0
3 years ago
Jorge earns $9,567 a month. Which number is $9,567 rounded to the nearest hundred?
Maksim231197 [3]
To find $9,567 rounded to the nearest hundred you must first find the hundreds place which is where 5 is then according to the number behind it you either round up or you keep 5 the same since the number behind 5 is 6 you round 5 up one which brings 5 to 6 now everything behind your new number is turned to 0. so your new amount would be $9,600
7 0
2 years ago
A tank with a capacity of 1600 L is full of a mixture of water and chlorine with a concentration of 0.0125 g of chlorine per lit
Veronika [31]

Answer:

y(t) = 20 [1600^(-5/3)] x (1600-24t)^ (5/3)

Step-by-step explanation:

1) Identify the problem

This is a differential equation problem

On this case the amount of liquid in the tank at time t is 1600−24t. (When the process begin, t=0 ) The reason of this is because the liquid is entering at 16 litres per second and leaving at 40 litres per second.

2) Define notation

y = amount of chlorine in the tank at time t,

Based on this definition, the concentration of chlorine at time t is y/(1600−24t) g/ L.

Since liquid is leaving the tank at 40L/s, the rate at which chlorine is leaving at time t is 40y/(1600−24t) (g/s).

For this we can find the differential equation

dy/dt = - (40 y)/ (1600 -24 t)

The equation above is a separable Differential equation. For this case the initial condition is y(0)=(1600L )(0.0125 gr/L) = 20 gr

3) Solve the differential equation

We can rewrite the differential equation like this:

dy/40y = -  (dt)/ (1600-24t)

And integrating on both sides we have:

(1/40) ln |y| = (1/24) ln (|1600-24t|) + C

Multiplying both sides by 40

ln |y| = (40/24) ln (|1600 -24t|) + C

And simplifying

ln |y| = (5/3) ln (|1600 -24t|) + C

Then exponentiating both sides:

e^ [ln |y|]= e^ [(5/3) ln (|1600-24t|) + C]

with e^c = C , we have this:

y(t) = C (1600-24t)^ (5/3)

4) Use the initial condition to find C

Since y(0) = 20 gr

20 = C (1600 -24x0)^ (5/3)

Solving for C we got

C = 20 / [1600^(5/3)] =  20 [1600^(-5/3)]

Finally the amount of chlorine in the tank as a function of time, would be given by this formula:

y(t) = 20 [1600^(-5/3)] x (1600-24t)^ (5/3)

7 0
3 years ago
the 90 members of a service Club had the opportunity to vote for a club officers on Tuesday or Wednesday 3/5 of the members vote
oee [108]
For this problem, it is really important to find who voted on Tuesday first.
90×(3/5)= 54 
54 people voted on Tuesday. Since the people who voted on Wednesday was 1/4 of the members who did not vote on Tuesday.
90-54=36×(1/4)=9
9 people voted on Wednesday. Now add Tuesday and Wednesday together to find the ones that didn't vote.
54+9=63;90-63=27
27 people did not vote at all.
6 0
2 years ago
Read 2 more answers
Find an equation of the tangent line to the graph of the function f(x) = 2sinx at the point where x = pi/3.
BigorU [14]
The equation of the tangent line of f(x) is given by y = f'(x)x + c
f(x) = 2sin x
f'(x) = 2cos x

At x = pi/3
f'(pi/3) = 2 cos(pi/3) = 1
f(pi/3) = 2 sin(pi/3) = √3
√3 = 1(π/3) + c
c = √3 - π/3

Therefore, required equation is
y = x + √3 - π/3
3 0
3 years ago
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