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yawa3891 [41]
3 years ago
6

Solve ABC c=10, B=35°, C=65%​

Mathematics
1 answer:
NISA [10]3 years ago
5 0

Answer:

Part 1) The measure of angle A is A=80\°

Part 2) The length side of a is equal to a=10.9\ units

Part 3) The length side of b is equal to b=6.3\ units

Step-by-step explanation:

step 1

Find the measure of angle A

we know that

The sum of the internal angles of a triangle must be equal to 180 degrees

so

A+B+C=180\°

substitute the given values

A+35\°+65\°=180\°

A+100\°=180\°

A=180\°-100\°=80\°

step 2

Find the length of side a

Applying the law of sines

\frac{a}{sin(A)}=\frac{c}{sin(C)}

substitute the given values

\frac{a}{sin(80\°)}=\frac{10}{sin(65\°)}

a=\frac{10}{sin(65\°)}(sin(80\°))

a=10.9\ units

step 3

Find the length of side b

Applying the law of sines

\frac{b}{sin(B)}=\frac{c}{sin(C)}

substitute the given values

\frac{b}{sin(35\°)}=\frac{10}{sin(65\°)}

b=\frac{10}{sin(65\°)}(sin(35\°))

b=6.3\ units

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