Hi!
So, it looks like you're doing ratios.
Let's look at 9). If the model car is 4 inches long, and 1 inch equals 4 feet, than the actual car is 16 feet long. We know this because 4x4=16.
11) is also just as simple. If 1 cm is 11 km, and the two cities are 99 km apart, then on the map they are 9 cm apart. 11x9 is 99.
13) This is a 1:2 ratio. Basically, the flagpole's shadow is half of its height. You half the man's height to get a 3 foot shadow.
And, finally, 15)- if the model is 4 inches to the real life train's 3 feet, the actual train is 120 ft long, given that the model is 40 in long. 40x3=120.
I hope this helps! :)
Answer:
Part a, intersecting. Part B is one solution
and its 2 beachuse y=3x-5
and y=-x+7
brainlsit plz
If the stretch is proportional to the weight, it will satisfy
weight/(49 cm) = (135 N)/(21 cm)
weight = (49/21)×135 N
weight = 315 N
The weight of the fish would be 315 N.
If your equation is 2v + 7 = 3,
Subtract 7 from both sides to get 2v = -4
Then divide 2 on both sides and get v = -4/2
Then simplify to get v = $-2