Step-by-step explanation:
x - y + 5z = 29
y + 2z = 4
z = 7
since z = 7 we can use this value in second equation
y + 2×7 = 4 and y = -10
now we know the value of y we can solve the first equation
x -(-10) + 5×7 = 29
x + 10 + 35 = 29
x = -11
Answer:
72
Step-by-step explanation:
Let the number of candies = n
Tracy ate = 1/3 of n = n/3 remaining 2n / 3
she gave 1/4 of the remainder to her friend = 1/4 of ( n - n/3) = 2n / 12
the new remainder = (2n / 3) - (2n / 12) = n /2
she and her mom then ate altogether = 30
and the brother took from 1 to five, the number he took = x
and she has 3 left
( n/2) - 30 - x = 3
n = 2 ( 33 + x)
now we know that the candies could not be broken and x is between 1 to 5
n = 2 (33 + 1), 2 (33+2), 2(33 +3), 2 (33+ 4) and 2 (33 + 5) this are the possible values of n, ( 68, 70, 72, 74, 76) and the multiple of 3 is 72
n therefore = 72
Step-by-step explanation:
hope this will help you mark me as brinalist friend please
Answer: 36
Step-by-step explanation:
6/2= 3 & 3x2=6 & 27/9=3 & 3x9=27 so you would multiply 3x12=36 so you would just multiply. and I'm a 6th grader.
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Answer:
(a) 6² +3² +1² +1² = 47
(b) 5² +4² +2² +1² +1² = 47
(c) 3³ +4² +2² = 47
Step-by-step explanation:
It can work reasonably well to start with the largest square less than the target number, repeating that approach for the remaining differences. When more squares than necessary are asked for, then the first square chosen may need to be the square of a number 1 less than the largest possible.
The approach where a cube is required can work the same way.
(a) floor(√47) = 6; floor(√(47 -6^2)) = 3; floor(√(47 -45)) = 1; floor(√(47-46)) = 1
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(b) floor(√47 -1) = 5; floor(√(47-25)) = 4; ...
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(c) floor(∛47) = 3; floor(√(47 -27)) = 4; floor(√(47 -43)) = 2
