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3 years ago

What is the area of a square picture with 16 inch sides

Mathematics

2 answers:

galben [10]3 years ago

6 0

Do 16 times 16. That's 256.

Arte-miy333 [17]3 years ago

4 0

Hello!

To find the area, you take one side, (16) and multiply it by that number..

So, 16 * 16 = 256.

The area of a square with 16in sides is 256.

Hope this helps! ☺♥

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*the problem is in the pic that is uploaded

Alex787 [66]

Hmm,
ok,
complete square ok
wait wat

he went from
(x-3)²=16 to
x-3=16
?????
he square rooted the left side only
he has to do it to both sides

he should have done
(x-3)²=16
x-3=+/-4
x=3+/-4
x=7 or -1

8 0

3 years ago

I need to find side x in its simplest radical form using the special right triangles method

crimeas [40]

Answer:

\sqrt{6}

Explanation:

From the given diagram,

Hypotenuse sde = x

Opposite side = \sqrt{3}

Using the SOH CAH TOA identity

Sintheta = opposite/hypotenuse

Sin 45 = \sqrt{3}/x

x = \sqrt{3}/sin45

$\begin{gathered} x\text{ =}\frac{\sqrt[]{3}}{\sin 45} \\ x\text{ = }\frac{\sqrt[]{3}}{\frac{1}{\sqrt[]{2}}} \\ x\text{ = }\sqrt[]{3^{}}\cdot\sqrt[]{2} \\ x\text{ =}\sqrt[]{6} \end{gathered}$

Hence the value of x is \sqrt{6}

5 0

1 year ago

Select the correct number of solutions and description of the corresponding graph for two lines that have the same slope but dif

BaLLatris [955]

Answer:

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

How many pairs of consecutive natural numbers have a product of less than 40000? I am in 5th grade. This is supposed to be easy

Ugo [173]

Answer:

There are 199 pairs of consecutive natural numbers whose product is less than 40000.

Step-by-step explanation:

We notice that such statement can be translated into this inequation:

$n \cdot (n+1) < 40000$

Now we solve this inequation to the highest value of $n$ that satisfy the inequation:

$n^{2}+n < 40000$

$n^{2}+n -40000$

The Quadratic Formula shows that roots are:

$n_{1,2} = \frac{-1\pm\sqrt{1^{2}-4\cdot (1)\cdot (-40000)}}{2\cdot (1)}$

$n_{1,2} = -\frac{1}{2}\pm \frac{1}{2} \cdot \sqrt{160001}$

$n_{1} = -\frac{1}{2}+\frac{1}{2}\cdot \sqrt{160001}$

$n_{1} \approx 199.501$

$n_{2} = -\frac{1}{2}-\frac{1}{2}\cdot \sqrt{160001}$

$n_{2} \approx -200.501$

Only the first root is valid source to determine the highest possible value of $n$ , which is $n_{max} = 199$ . Each natural number represents an element itself and each pair represents an element as a function of the lowest consecutive natural number. Hence, there are 199 pairs of consecutive natural numbers whose product is less than 40000.

6 0

3 years ago

Quadrilateral qrst is a square what is pst

hodyreva [135]

if QRST is indeed a quadrilateral, then, Check the picture below.

3 0

3 years ago