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masya89 [10]
3 years ago
6

Is the relation a function? {(14,9), (15,8), (8, 7), (1,9), (15, 2)

Mathematics
1 answer:
zubka84 [21]3 years ago
5 0

Answer:

No the relation is not a function

Step-by-step explanation:

This is because there are 2 x factors that have the value of 15. (15,8) and (15,2)

in order to make this a function you would have to change the one of the x factor of the 2 ratios:

(15,8) and (15,2)

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5 0
3 years ago
I don't understand how to do this problem.
Delicious77 [7]
Answers: 

x = 4
EF = 14
CF = 7
EC = 7

-------------------------------------------------------------
-------------------------------------------------------------

Work Shown:

C is the midpoint of segment EF. This means that EC = CF. In other words, the two pieces are congruent. 

Use substitution and solve for x
EC = CF
5x-13 = 3x-5
5x-13+13 = 3x-5+13
5x = 3x+8
5x-3x = 3x+8-3x
2x = 8
2x/2 = 8/2
x = 4

Now that we know that x = 4, we can use this to find EC and CF

Let's compute EC
EC = 5x - 13
EC = 5*x - 13
EC = 5*4 - 13 ... replace x with 4
EC = 20 - 13
EC = 7

Let's compute CF
CF = 3x - 5
CF = 3*x - 5
CF = 3*4 - 5 ... replace x with 4
CF = 12 - 5
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As expected, EC = CF (both are 7 units long).

By the segment addition postulate, we can say EC+CF = EF

EC+CF = EF
EF = EC+CF
EF = 7+7
EF = 14
8 0
3 years ago
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