Is the relation a function? {(14,9), (15,8), (8, 7), (1,9), (15, 2)
1 answer:
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Answer:
320 Student Tickets
180 Adult Tickets
Step-by-step explanation:
You can solve this problem by using system of equations. First, we need to figure out our equations.
Equation 1: x as students and y as adults
We get this equation because the total tickets sold was 500. The x represents the students sold to students, and the y represents the tickets sold to adults.
Equation 2:
We get this equation based on the prices. Each student ticket costs $3, and each adult ticket costs $5. The total amount earned was $1850.
Now that we have out equations, we can use system of equations to find our students and adults.
Typically elimination is the easiest strategy because you are able to cross out variables.
Becomes:
We see that both equations now have 3x. We can cancel out 3x.
Now that we know y=180, we can plug it back into one of our equations to find x.
320 student tickets and 180 adult tickets were sold.
For this equation, you want to do it in fractions/ratios to properly solve it. You would have his average misses out of every field goal and his real missed attempts over total. It would look like this
= 
You want to solve for x since x is the total amount of field goals that he attempted. You can do this by doing cross multiplication:
(2)(x) = (8)(11)
From here you can get:
2x = 88
Divide each side by 2 to isolate x and you get:
x= 44
So he made a total of 44 field goals.
You want to solve for x since x is the total amount of field goals that he attempted. You can do this by doing cross multiplication:
(2)(x) = (8)(11)
From here you can get:
2x = 88
Divide each side by 2 to isolate x and you get:
x= 44
So he made a total of 44 field goals.