Answer:
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
Step-by-step explanation:
If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -
x = ( 30 cos 20° )( time ),
y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2
To determine " ( 30 cos 20° )( time ) " you would do the following calculations -
( x = 30 * 0.93... = ( About ) 28.01t
This represents our horizontal distance, respectively the vertical distance should be the following -
y = 30 * 0.34 - 4.9t^2,
( y = ( About ) 10.26t - 4.9t^2 + 2
In other words, our solution should be,
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
<u><em>These are are parametric equations</em></u>
Answer:
Fraction: x = 247/21
Decimal: 11.76
Mixed Number: 11 16/21
Step-by-step explanation:
Brainliest Please!!
Answer:
14.13 ft²
Step-by-step explanation:
The area of a semicircle is
We were given the radius of the semicircle to be: r=3 feet.
We were also asked to use π as 3.14.
We substitute into the formula to get:
This is the same as:
Or
The area of the semicircle is 14.13 ft²
Answer:
4 because I know it's right
