Step-by-step explanation:
From this figure TUW+WUV=TUV ; (5x+3)+(10x-5)=17x-16 so 15x-2=17x-16 ;14=2x therefore x=7
then substitute x on it.
TUW=5x+3=5(7)+3=35+3=38
WUV=10x-5=10(7)-5=70-5=65
TUV=17x-16=17(7)-16=119-16=103
Answer:
look at the picture i have sent
Answer:
x = ±2
Step-by-step explanation:
3x ^2 -4 = 8
Add 4 to each side
3x ^2 -4+4 = 8+4
3x^2 =12
Divide each side by 3
3x^2 =12
3x^2/3 = 12/3
x^2 = 4
Take the square root of each side
sqrt(x^2) = ±sqrt(4)
x = ±2
The mass of each candy is 80 grams
We will form the equations for this problem:
(1) 1100*y + z = 113
(2) 1500*y + z = 153
z = ? Monthly administration fee is notated with z, and that is the this problem's question.
Number of kilowatt hours of electricity used are numbers 1100 and 1500 respectively.
Cost per kilowatt hour is notated with y, but its value is not asked in this math problem, but we can calculate it anyway.
The problem becomes two equations with two unknowns, it is a system, and can be solved with method of replacement:
(1) 1100*y + z = 113
(2) 1500*y + z = 153
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(1) z = 113 - 1100*y [insert value of z (right side) into (2) equation instead of z]:
(2) 1500*y + (113 - 1100*y) = 153
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(1) z = 113 - 1100*y
(2) 1500*y + 113 - 1100*y = 153
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(1) z = 113 - 1100*y
(2) 400*y + 113 = 153
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(1) z = 113 - 1100*y
(2) 400*y = 153 - 113
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(1) z = 113 - 1100*y
(2) 400*y = 40
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(1) z = 113 - 1100*y
(2) y = 40/400
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(1) z = 113 - 1100*y
(2) y = 1/10
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if we insert the obtained value of y into (1) equation, we get the value of z:
(1) z = 113 - 1100*(1/10)
(1) z = 113 - 110
(1) z = 3 dollars is the monthly fee.